Question

我有一个根据已发布的元数据层的变化动态改变我的SQL2K5表结构的过程。

例如，如果需要添加新列并且表没有依赖项，则步骤为： 1.使用T-SQL为任何索引创建脚本＆amp;表中已存在的主键[这些脚本包含在下面] 2.放下桌子 3.从具有新列的元图层重新创建表 4.执行步骤1中创建的脚本 5.使用BulkCopy填充表格

以上内容是通过.NET程序集启动的，每天在3个并发流中运行。

我在步骤＃1中收到死锁错误 - 当我访问INFORMATION_SCHEMA表以编写索引/键时。我在这些脚本中使用了提示WITH（NOLOCK），认为这可以防止在这些操作的3个流同时运行时发生任何锁定。表只能在1个流中处理（创建或编写脚本）。

我还需要做些什么吗？

任何评论都非常感谢。

[脚本]

ALTER Procedure [dbo].[s$spScriptPrimaryKeyForTable]
@Tablename varchar(100)
AS 


-- Get all existing primary keys
DECLARE cPK CURSOR FOR
SELECT TABLE_NAME, CONSTRAINT_NAME 
FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS WITH(NOLOCK)
WHERE upper(TABLE_NAME)=upper(@Tablename)
ORDER BY TABLE_NAME

DECLARE @PkTable SYSNAME
DECLARE @PkName SYSNAME

-- Loop through all the primary keys
OPEN cPK
FETCH NEXT FROM cPK INTO @PkTable, @PkName
WHILE (@@FETCH_STATUS = 0)
BEGIN
DECLARE @PKSQL NVARCHAR(4000) SET @PKSQL = ''
SET @PKSQL = 'ALTER TABLE ' + @PkTable + ' ADD CONSTRAINT ' + @PkName + ' PRIMARY KEY CLUSTERED ('

-- Get all columns for the current primary key
DECLARE cPKColumn CURSOR FOR
SELECT COLUMN_NAME 
FROM INFORMATION_SCHEMA.KEY_COLUMN_USAGE WITH(NOLOCK)
WHERE TABLE_NAME = @PkTable AND CONSTRAINT_NAME = @PkName
ORDER BY ORDINAL_POSITION
OPEN cPKColumn

DECLARE @PkColumn SYSNAME
DECLARE @PkFirstColumn BIT SET @PkFirstColumn = 1
-- Loop through all columns and append the sql statement
FETCH NEXT FROM cPKColumn INTO @PkColumn
WHILE (@@FETCH_STATUS = 0)
BEGIN
IF (@PkFirstColumn = 1)
SET @PkFirstColumn = 0
ELSE
SET @PKSQL = @PKSQL + ', '

SET @PKSQL = @PKSQL + @PkColumn

FETCH NEXT FROM cPKColumn INTO @PkColumn
END
CLOSE cPKColumn
DEALLOCATE cPKColumn

SET @PKSQL = @PKSQL + ')'
-- Print the primary key statement
-- PRINT @PKSQL

FETCH NEXT FROM cPK INTO @PkTable, @PkName
END
CLOSE cPK
DEALLOCATE cPK


SELECT ISNULL(@PKSQL,' ')

================

ALTER Procedure [dbo].[s$spScriptIndexesForTable]
@Tablename varchar(100)

AS 

DECLARE @RetVal varchar(4000)
SET @RetVal = ''

-- Get all existing indexes, but NOT the primary keys 
DECLARE cIX CURSOR FOR 
SELECT OBJECT_NAME(SI.Object_ID), SI.Object_ID, SI.Name, SI.Index_ID 
FROM Sys.Indexes SI WITH(NOLOCK)
LEFT JOIN INFORMATION_SCHEMA.TABLE_CONSTRAINTS TC WITH(NOLOCK) ON SI.Name = TC.CONSTRAINT_NAME AND OBJECT_NAME(SI.Object_ID) = TC.TABLE_NAME 
WHERE TC.CONSTRAINT_NAME IS NULL 
AND OBJECTPROPERTY(SI.Object_ID, 'IsUserTable') = 1 
AND upper(OBJECT_NAME(SI.Object_ID))=upper(@Tablename)
ORDER BY OBJECT_NAME(SI.Object_ID), SI.Index_ID 

DECLARE @IxTable SYSNAME 
DECLARE @IxTableID INT 
DECLARE @IxName SYSNAME 
DECLARE @IxID INT 

-- Loop through all indexes 
OPEN cIX 
FETCH NEXT FROM cIX INTO @IxTable, @IxTableID, @IxName, @IxID 
WHILE (@@FETCH_STATUS = 0) 
BEGIN 
DECLARE @IXSQL NVARCHAR(4000) 
--SET @PKSQL = '' 
SET @IXSQL = 'CREATE ' 

-- Check if the index is unique 
IF (INDEXPROPERTY(@IxTableID, @IxName, 'IsUnique') = 1) 
SET @IXSQL = @IXSQL + 'UNIQUE ' 
-- Check if the index is clustered 
IF (INDEXPROPERTY(@IxTableID, @IxName, 'IsClustered') = 1) 
SET @IXSQL = @IXSQL + 'CLUSTERED ' 

SET @IXSQL = @IXSQL + 'INDEX ' + @IxName + ' ON [' + @IxTable + '] (' 

-- Get all columns of the index 
DECLARE cIxColumn CURSOR FOR 
SELECT SC.Name,IC.[is_included_column],IC.is_descending_key 
FROM Sys.Index_Columns IC WITH(NOLOCK)
JOIN Sys.Columns SC WITH(NOLOCK) ON IC.Object_ID = SC.Object_ID AND IC.Column_ID = SC.Column_ID 
WHERE IC.Object_ID = @IxTableID AND Index_ID = @IxID 
ORDER BY IC.Index_Column_ID,IC.is_included_column 

DECLARE @IxColumn SYSNAME 
DECLARE @IxIncl bit 
DECLARE @Desc bit 
DECLARE @IxIsIncl bit set @IxIsIncl = 0 
DECLARE @IxFirstColumn BIT SET @IxFirstColumn = 1 

-- Loop throug all columns of the index and append them to the CREATE statement 
OPEN cIxColumn 
FETCH NEXT FROM cIxColumn INTO @IxColumn, @IxIncl, @Desc 
WHILE (@@FETCH_STATUS = 0) 
BEGIN 

IF (@IxFirstColumn = 1) 
BEGIN 
SET @IxFirstColumn = 0 
END 
ELSE 
BEGIN 
--check to see if it's an included column 
IF ((@IxIsIncl = 0) AND (@IxIncl = 1)) 
BEGIN 
SET @IxIsIncl = 1 
SET @IXSQL = @IXSQL + ') INCLUDE (' 
END 
ELSE 
BEGIN 
SET @IXSQL = @IXSQL + ', ' 
END 
END 

SET @IXSQL = @IXSQL + '[' + @IxColumn + ']' 
--check to see if it's DESC 
IF @Desc = 1 
SET @IXSQL = @IXSQL + ' DESC' 

FETCH NEXT FROM cIxColumn INTO @IxColumn, @IxIncl, @Desc 
END 
CLOSE cIxColumn 
DEALLOCATE cIxColumn 

SET @IXSQL = @IXSQL + ')' 

-- Print out the CREATE statement for the index 
--SELECT 'IXSQL: ' + @IXSQL
IF @RetVal IS NULL
SET @RetVal = ''
--SELECT 'Retval: ' + @RetVal
SET @RetVal = @RetVal + @IXSQL + ' ' 

FETCH NEXT FROM cIX INTO @IxTable, @IxTableID, @IxName, @IxID 
END 

CLOSE cIX 
DEALLOCATE cIX 

SELECT ISNULL(@RetVal,' ')

Answer 1

INFORMATION_SCHEMA视图就是 - 视图。您无法更新它们，因此它们不太可能导致任何死锁。如果你想确定真正的来源（我假设它与你的改变有关，或光标中你没有显示的其他代码，或者你正在调用的其他代码与调用这些程序 - 因为选择反对视图然后选择变量不是原因），我建议阅读Gail Shaw's blog post on interpreting deadlocks。
尽管（1）我仍然建议使用比INFORMATION_SCHEMA更多的现代目录视图。例如，可以从sys.key_constraints派生相同的信息。
您正在使用默认光标选项;而你正在嵌套游标。如果最终仍然使用游标，则应养成使用资源较少的游标（例如LOCAL STATIC FORWARD_ONLY READ_ONLY）的习惯。

您实际上并不需要游标来执行此操作。以下是我将如何重写PK表脚本：

CREATE PROCEDURE dbo.ScriptPKForTable
    @TableName SYSNAME
AS
BEGIN
    SET NOCOUNT ON;

    DECLARE 
      @pkName    SYSNAME,
      @clustered BIT,
      @object_id INT,
      @sql       NVARCHAR(MAX);

    SELECT
      @object_id = OBJECT_ID(UPPER(@TableName));

    SELECT
      @pkName = kc.name,
      @clustered = CASE i.[type] 
        WHEN 1 THEN 1 ELSE 0 END
    FROM 
        sys.key_constraints AS kc
    INNER JOIN 
        sys.indexes AS i
        ON kc.parent_object_id = i.[object_id]
        AND kc.unique_index_id = i.index_id
    WHERE
        kc.parent_object_id = @object_id
        AND kc.[type] = 'pk';

    SET @sql = N'ALTER TABLE ' + QUOTENAME(@TableName)
      + ' ADD CONSTRAINT ' + @pkName 
      + ' PRIMARY KEY ' + CASE @clustered 
      WHEN 1 THEN 'CLUSTERED' ELSE '' END + ' (';

    SELECT
      @sql = @sql + c.name + ','
    FROM 
      sys.index_columns AS ic
    INNER JOIN
      sys.indexes AS i 
      ON ic.index_id = i.index_id
      AND ic.[object_id] = i.[object_id]
    INNER JOIN 
      sys.key_constraints AS kc
      ON i.[object_id] = kc.[parent_object_id]
      AND kc.unique_index_id = i.index_id
    INNER JOIN 
      sys.columns AS c
      ON i.[object_id] = c.[object_id]
      AND ic.column_id = c.column_id
    WHERE
      kc.[type] = 'PK'
      AND kc.parent_object_id = @object_id
    ORDER BY key_ordinal;

    SET @sql = LEFT(@sql, LEN(@sql) - 1) + ');';

    SELECT COALESCE(@sql, ' ');
END
GO

至于索引创建脚本，我认为有一种更好的方法可以做到这一点（同样没有明确的游标，不是避免光标是目标，但代码将变得更加清洁）。首先，您需要一个函数来构建索引中的键或包含列：

CREATE FUNCTION dbo.BuildIndexColumns
(
    @object_id        INT,
    @index_id         INT,
    @included_columns BIT
)
RETURNS NVARCHAR(MAX)
AS
BEGIN
  DECLARE @s NVARCHAR(MAX);

  SELECT @s = N'';

  SELECT @s = @s + c.name + CASE ic.is_descending_key
    WHEN 1 THEN ' DESC' ELSE '' END + ',' 
    FROM sys.index_columns AS ic
    INNER JOIN sys.columns AS c
    ON ic.[object_id] = c.[object_id]
    AND ic.column_id = c.column_id
    WHERE c.[object_id] = @object_id
    AND ic.[object_id] = @object_id
    AND ic.index_id = @index_id
    AND ic.is_included_column = @included_columns
    ORDER BY ic.key_ordinal;

  IF @s > N''
    SET @s = LEFT(@s, LEN(@s)-1);

  RETURN (NULLIF(@s, N''));
END
GO

使用该函数，ScriptIndexes过程非常简单：

CREATE PROCEDURE dbo.ScriptIndexesForTable
    @TableName SYSNAME
AS
BEGIN
  SET NOCOUNT ON;

  DECLARE
      @sql       NVARCHAR(MAX),
      @object_id INT;

  SELECT @sql = N'', @object_id = OBJECT_ID(UPPER(@TableName));

  SELECT @sql = @sql + 'CREATE '
      + CASE i.is_unique WHEN 1 THEN 'UNIQUE ' ELSE '' END
      + CASE i.[type] WHEN 1 THEN 'CLUSTERED ' ELSE '' END
      + ' INDEX ' + i.name + ' ON ' + QUOTENAME(@TableName) + ' (' 
      + dbo.BuildIndexColumns(@object_id, i.index_id, 0)
      + ')' + COALESCE(' INCLUDE(' 
      + dbo.BuildIndexColumns(@object_id, i.index_id, 1)
      + ')', '') + ';' + CHAR(13) + CHAR(10)
  FROM
      sys.indexes AS i
  WHERE
      i.[object_id] = @object_id
      -- since this will be covered by ScriptPKForTable:
      AND i.is_primary_key = 0
  ORDER BY i.index_id;

  SELECT COALESCE(@sql, ' ');
END
GO

请注意，我的解决方案并不假设PK是群集的（您的PK脚本硬编码CLUSTERED，但您的索引脚本假定任何索引都可以群集）。我还忽略了其他属性，例如文件组，分区或过滤索引（2005年不支持）。

查询INFORMATION_SCHEMA时出现死锁

1 个答案: