Question

我通过curl发布数据登录了一个网站。我现在想要显示用户登录后通常会看到的页面，但我不能，因为网址总是在变化。

http://some.example.com/niceday/foobar.php?TID= ABCD 其中 abcd 是一些看似随机的数字。

我一直在尝试获取响应标头，但它一直向我提供我刚刚发送的请求标头。

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, 'http://example.com/niceday/dirlogin.php'); //login URL
curl_setopt ($ch, CURLOPT_POST, 1);
$postData = 'userName=scott&password=abc123& etc...';
curl_setopt($ch, CURLOPT_POSTFIELDS, $postData);
curl_setopt($ch, CURLOPT_COOKIEJAR, 'cookie.txt');
curl_setopt( $ch, CURLOPT_FOLLOWLOCATION, true );
curl_setopt( $ch, CURLOPT_ENCODING, "" );
curl_setopt( $ch, CURLOPT_AUTOREFERER, true );
curl_setopt ($ch, CURLOPT_HEADER, true);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_NOBODY, true); 
$store = curl_exec($ch);
$info = curl_getinfo($ch);
print_r($info);//wrong headers are printed out

显示了curl_exec（$ ch）的标题但是如何获取响应标头？我不确定它是否相关，但输入登录凭据的表单使用javascript

Answer 1

你可以获得响应标题：$headers = curl_getinfo($ch);但是我看不出它如何帮助你解决问题，然后你可以使用http_parse_header()或explode("\n", $headers);

更新：

$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, 'http://www.mozilla.org/');
curl_setopt ($ch, CURLOPT_HEADER, true);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_NOBODY, true); // HTTP request is 'HEAD'
$headers=curl_exec($ch);

这将只返回标题。

Answer 2

试试这个：

<?php

function my_get_headers($url ) {

       $url_info=parse_url($url);
       if (isset($url_info['scheme']) && $url_info['scheme'] == 'https') {
           $port = 443;
           @$fp=fsockopen('ssl://'.$url_info['host'], $port, $errno, $errstr, 10);
       } else {
           $port = isset($url_info['port']) ? $url_info['port'] : 80;
           @$fp=fsockopen($url_info['host'], $port, $errno, $errstr, 10);
       }
       if($fp) {
           stream_set_timeout($fp, 10);
           $head = "HEAD ".@$url_info['path']."?".@$url_info['query'];
           $head .= " HTTP/1.0\r\nHost: ".@$url_info['host']."\r\n\r\n";
           fputs($fp, $head);
           while(!feof($fp)) {
               if($header=trim(fgets($fp, 1024))) {
                        $sc_pos = strpos( $header, ':' );
                        if( $sc_pos === false ) {
                           $headers['status'] = $header;
                        } else {
                            $label = substr( $header, 0, $sc_pos );
                            $value = substr( $header, $sc_pos+1 );
                            $headers[strtolower($label)] = trim($value);
                        }
               }
           }
           return $headers;
       }
       else {
           return false;
       }
   }

   print_r( my_get_headers("http://www.mozilla.org"));  

?>

输出：

Array
(
    [status] => HTTP/1.1 200 OK
    [server] => Apache
    [x-backend-server] => pm-web01
    [content-type] => text/html; charset=UTF-8
    [date] => Mon, 15 Aug 2011 14:26:16 GMT
    [keep-alive] => timeout=20, max=999
    [expires] => Mon, 15 Aug 2011 00:36:16 GMT
    [connection] => close
    [x-powered-by] => PHP/5.2.9
    [x-cache-info] => not cacheable; response has already expired
)

功能 my_get_headers 被盗http://www.php.net/manual/en/function.get-headers.php#64073

Answer 3

get_gheaders的文档说：“获取服务器发送的所有标头以响应HTTP请求”。实际应该是：“获取服务器发送的所有标头，以响应导致当前脚本执行的HTTP请求”。

从响应通过curl发出的请求获取位置标头时遇到问题

3 个答案: