Question

如何编写一个在字符串中对字母，数字和标点符号（单独）进行计数的程序？

Answer 1

对于稍微更精简/更快的版本，还有

count = lambda l1，l2：sum（如果x在l2中，则为l中的x为1）

所以例如：

count = lambda l1,l2: sum([1 for x in l1 if x in l2])

In [11]: s = 'abcd!!!'

In [12]: count(s,set(string.punctuation))                                                                                                      
Out[12]: 3

使用套装可以在某种程度上提高你的速度。

也取决于字符串的大小我认为你应该获得对过滤器的记忆优势。

Answer 2

import string
a = "I'm not gonna post my homework as question on OS again, I'm not gonna..."

count = lambda l1, l2: len(list(filter(lambda c: c in l2, l1)))

a_chars =  count(a, string.ascii_letters)
a_punct = count(a, string.punctuation)

Answer 3

count_chars = ".arPZ"
string = "Phillip S. is doing a really good job."
counts = tuple(string.count(c) for c in count_chars)

print counts

（2,2,1,1,0）

Answer 4

>>> import string
>>> import operator
>>> import functools
>>> a = "This, is an example string. 42 is the best number!"
>>> letters = string.ascii_letters
>>> digits = string.digits
>>> punctuation = string.punctuation
>>> letter_count = len(filter(functools.partial(operator.contains, letters), a))
>>> letter_count
36
>>> digit_count = len(filter(functools.partial(operator.contains, digits), a))
>>> digit_count
2
>>> punctuation_count = len(filter(functools.partial(operator.contains, punctuation), a))
>>> punctuation_count
3

http://docs.python.org/library/string.html

http://docs.python.org/library/operator.html#operator.contains

http://docs.python.org/library/functools.html#functools.partial

http://docs.python.org/library/functions.html#len

http://docs.python.org/library/functions.html#filter

Answer 5

要遍历字符串，您可以使用for循环：

for c in "this is a test string with punctuation ,.;!":
    print c

输出：

t
h
i
s
...

现在，您所要做的就是计算事件...

计算字符串中的字母数字和标点符号

5 个答案: