我创建了一个名为DataClass的类,我有这个方法
+(NSMutableArray*) returnList :(NSString *) sql
{
NSMutableArray *tmpList=[[[NSMutableArray alloc]init]autorelease];
sqlite3 *db;
NSString *dbPath =[[NSBundle mainBundle] pathForResource:@"DB_MyReef" ofType:@"sqlite"];
if (sqlite3_open([dbPath UTF8String],&db) ==SQLITE_OK)
{
sqlite3_stmt *ss;
int rv = sqlite3_prepare_v2(db, [sql UTF8String], -1,&ss,NULL);
if (rv==SQLITE_OK)
{
while (sqlite3_step(ss)==SQLITE_ROW)
{
NSString *txt =[NSString stringWithUTF8String:(char *)sqlite3_column_text(ss,0)];
[tmpList addObject:txt];
[txt release];
}
}
sqlite3_finalize(ss);
}
sqlite3_close(db);
return tmpList;
}
在我创建的另一个名为UserSelect的类中。
在h文件中
@interface UserSelect : UIViewController <UIPickerViewDelegate,UIPickerViewDataSource> {
NSMutableArray *List;
UIPickerView *myPicker;
}
@property (nonatomic,retain) NSMutableArray *List;
@property (nonatomic,retain) UIPickerView *myPicker;
@end
和m文件
- (void)viewDidLoad {
[super viewDidLoad];
//List=[[NSMutableArray alloc] init;
NSString *sql;
//Loading Data
if ([self.title isEqualToString:@"Marca Teste"])
{
sql=@"SELECT TESTMARK FROM TBL_TESTSMARK ORDER BY TESTMARK";
}
else
{
sql=@"SELECT PT_PARAMNAME FROM TBL_PARAMETERS "
"WHERE COD IN "
"(SELECT A.CODTEST FROM TBL_TEST AS A "
"INNER JOIN "
"TBL_TESTSMARK AS B "
"ON "
"A.CODTESTMARK =B.COD "
"WHERE "
"B.TESTMARK='Salifert')";
}
self.List=[[NSMutableArray alloc] init];
self.List=[[NSMutableArray arrayWithArray:[DataClass returnList:sql]]retain];
myPicker=[[UIPickerView alloc] init];
myPicker.delegate=self;
myPicker.dataSource=self;
/*for (NSString *ts in List) {
NSLog(@"%@",ts);
}*/
[self.view addSubview:myPicker];
}
好的,我打电话给这个方法,这个回归是预期的。
但是在UiPickerView方法中,我的List变量只保留NSMutable数组中的第一个对象。
这些是UIPicker方法
#pragma mark pickerView
-(NSInteger)numberOfComponentsInPickerView:(UIPickerView *)pickerView
{
NSLog(@"%@",@"numberOfComponentsInPickerView");
return 1;
}
-(NSInteger)pickerView:(UIPickerView *)pickerView numberOfRowsInComponent:(NSInteger)component
{
NSLog(@"%@",@"numberOfRowsInComponent");
return [List count];
}
-(NSString *)pickerView:(UIPickerView *) pickerView titleForRow:(NSInteger) row forComponent:(NSInteger) component
{
NSString *txt=[[NSString alloc] initWithFormat:@"%@",[self.List objectAtIndex:(int)row]];
return txt;
[txt release];
}
-(void)pickerView:(UIPickerView *)pickerView didSelectRow:(NSInteger)row inComponent:(NSInteger)component
{
NSString *txt=[[NSString alloc] initWithFormat:@"%@",[self.List objectAtIndex:(int)row]];
[DataClass writePlist:txt toKey:TEST_MARK];
[txt release];
}
我试图以多种方式启动List,出了什么问题?
答案 0 :(得分:1)
看看这里:
NSString *txt =[NSString stringWithUTF8String:(char *)sqlite3_column_text(ss,0)];
[tmpList addObject:txt];
[txt release];
字符串txt是自动释放的(NSString stringXXX
函数返回自动释放的字符串)。然后将其添加到tmpList
并明确释放它。一旦自动释放池耗尽,该字符串将被释放。换句话说,你过度释放字符串。删除
[txt release];
并且值应由tmpList
保留。由于tmpList也是自动释放的,因此不确定这是否重要。它可能会给你一个运行时错误。
这也是可疑的:
self.List=[[NSMutableArray alloc] init];
self.List=[[NSMutableArray arrayWithArray:[DataClass returnList:sql]]retain];
第一个alloc-init完全没必要。如果属性合理,它不会产生泄漏,但它没有任何意义。删除这两行中的第一行。
此外,您的returnList:
方法返回一个字符串,但您在上面引用的第二行中将其用作数组。
总而言之,您的代码中存在相当多的逻辑错误。您可能希望通过调试器和分析器运行它(菜单Product - Analyze)。