Question

我想在获取数据库结果的同时在while循环中使用json_encode()。这是我的代码：

<?

$database = sqlite_open("thenew.db", 0999, $error);
if(!$database) die($error);

$query = "SELECT * FROM users";
$results = sqlite_query($database, $query);
if(!$results) die("Canot execute query");

while($row = sqlite_fetch_array($results)) {
  $data = $row['uid'] . " " . $row['username'] . " " . $row['xPos'] . " " . $row['yPos'];
}
echo json_encode(array("response"=>$data));

sqlite_close($database);

?>

这是

的输出

{“response”：“lastUserID lastUser lastXPos lastYPos”}

我希望它是......

{“回应”：[“1 Alex 10 12”，“2 Fred 27 59”，“3 Tom 47 19”}}

等

所以我希望json_encode()函数将所有用户放入数组而不是最后一个。我该怎么做？感谢

Answer 1

尝试：

<?

$database = sqlite_open("thenew.db", 0999, $error);
if(!$database) die($error);

$query = "SELECT * FROM users";
$results = sqlite_query($database, $query);
if(!$results) die("Canot execute query");

$data = array();

while($row = sqlite_fetch_array($results)) {
  $data[] = $row['uid'] . " " . $row['username'] . " " . $row['xPos'] . " " . $row['yPos'];
}
echo json_encode(array("response"=>$data));

sqlite_close($database);

?>

Answer 2

更改此

while($row = sqlite_fetch_array($results)) {
  $data = $row['uid'] . " " . $row['username'] . " " . $row['xPos'] . " " . $row['yPos'];
}

到

$data = array();
while($row = sqlite_fetch_array($results)) {
  $data[] = $row['uid'] . " " . $row['username'] . " " . $row['xPos'] . " " . $row['yPos'];
}

Answer 3

将每个用户推送到一个数组：

$data = array();
while($row = sqlite_fetch_array($results)) {
  $data[] = $row['uid'] . " " . $row['username'] . " " . $row['xPos'] . " " . $row['yPos'];
}
echo json_encode(array("response"=>$data));

PHP循环中的json_encode（）

3 个答案: