Question

在发送到线路之前，我遇到了序列化对象的问题。

基本上我希望我的对象被序列化为

<verb operation="and">Show</verb>

然而它忽略了属性

<verb>Show</verb>

以下是客户端代理代码

    /// <remarks/>
[System.CodeDom.Compiler.GeneratedCodeAttribute("svcutil", "3.0.4506.2152")]
[System.SerializableAttribute()]
[System.Xml.Serialization.XmlTypeAttribute(Namespace = "http://www.starstandards.org/webservices/2005/10/transport")]
public enum OperationEnumeratedType
{

    /// <remarks/>
    /// 
    and,

    /// <remarks/>
    /// 
    or,

    /// <remarks/>
    /// 
    not,
}


        /// <remarks/>
    [System.Xml.Serialization.XmlAttributeAttribute(Form = System.Xml.Schema.XmlSchemaForm.Qualified)]
    public OperationEnumeratedType operation
    {
        get
        {
            return this.operationField;
        }
        set
        {
            this.operationField = value;
        }
    }

以下是我如何创建此对象。

                    verb = new CriteriaLogicStringType
                    {
                        operation = OperationEnumeratedType.and,
                        Value = "Show"
                    }

有谁知道如何让操作属性出现在序列化的xml中？

由于

Answer 1

您应该使用EnumMemberAttribute装饰OperationEnumeratedType枚举的成员，如下所示：

[DataContract]
public enum OperationEnumeratedType
{
    [EnumMember]
    And,
    [EnumMember]
    Or, 
    [EnumMember]
    Not
}

相关资源：

Enumeration Types in Data Contracts

忽略了WCF枚举属性的XMLSerialization

1 个答案: