Question

我运行此查询

        $result1 = mysql_query("SELECT * FROM 'departments'");
        while($row1 = mysql_fetch_assoc($result1))
        {
            $depts = array("Name" => $row1['Name'], "Value" => $row1['Value'], "ID" => $row['CollegeID']);
        }

使用其他三个简单查询，一个将数据加载到配置文件文本框中，另一个加载下拉列表。我的查询或我的PHP代码可能导致此错误。它只返回约51条记录。您是否认为它可能是MySQL服务器在2008 Windows Server上运行的服务器。

Answer 1

也许你在departments表中有很多列。试试这个：

    $result1 = mysql_query("SELECT Name, Value, CollegeID  FROM 'departments'");
    while($row1 = mysql_fetch_assoc($result1))
    {
        $depts = array("Name" => $row1['Name'], "Value" => $row1['Value'], "ID" => $row['CollegeID']);
    }

Answer 2

您也可以尝试使用OOP mysqli函数而不是旧的mysql版本。

$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
$mysqli->query("SELECT Name, Value, CollegeID  FROM departments");

Answer 3

绝不使用*

$result1 = mysql_query("SELECT Name, Value, CollegeID  FROM 'departments'");
while($row1 = mysql_fetch_assoc($result1))
{
    $depts = array("Name" => $row1['Name'], "Value" => $row1['Value'], "ID" => $row['CollegeID']);
}

并使用LIMIT

$result1 = mysql_query("SELECT Name, Value, CollegeID  FROM 'departments' LIMIT 1");
while($row1 = mysql_fetch_assoc($result1))
{
    $depts = array("Name" => $row1['Name'], "Value" => $row1['Value'], "ID" => $row['CollegeID']);
}

在您的情况下无关紧要，因为您总是用新的一行覆盖实际的$depts变量

MySQL Query正在减慢页面加载速度

3 个答案: