Question

我有以下代码：

gchar **split = g_strsplit(str, "\n", 0);
gchar **pointer = NULL;
GRegex *line_regex = NULL;
GMatchInfo *info = NULL;
line_regex = g_regex_new("^.*:(\\d+):.*$", 0, 0, NULL);

gtk_list_store_clear(store);
gtk_list_store_clear(store);
for (pointer = split; *pointer; pointer++)
    if (strlen(*pointer)){
        gchar *word = "";
        if (line_regex && g_regex_match(line_regex, *pointer, 0, &info)){
            if (g_match_info_matches(info)){
                word = g_match_info_fetch(info, 0);
            }
        }
        gtk_list_store_insert_with_values(store, NULL, -1, 0, word, 1, *pointer, -1);
    }

我想在组内获取值，这意味着跟随字符串：

some-test:56:some-other-text

我想得到56.我不知道gtk是如何工作的，所以我在这里有点失明，我在文档中找不到任何东西。在python我会使用groups方法，所以在这里我需要类似的东西。你能告诉我怎么去吗？

Answer 1

我在gnome.org的g-match-info-fetch page找到了有用的信息，表明g_match_info_fetch(info, 0)会返回整个匹配项，而^ ... $正则表达式就是整行。下面显示的代码（类似于您的代码，除了我用printf替换gtk_list_store内容）说明g_match_info_fetch(info, 1)返回您想要的字段。代码显示以下3行：

info 1 =   56,   info 0 = a-test:56:some-other-text
No match in b-test:283B:some-other-text
info 1 =  718,   info 0 = c-test:718:some-other-text

以下是代码：

#include <string.h>
#include <gtk/gtk.h>
int main(void) {
  char *str = "a-test:56:some-other-text\nb-test:283B:some-other-text\nc-test:718:some-other-text\n";
  gchar **split = g_strsplit(str, "\n", 0);
  gchar **pointer = NULL;
  GRegex *line_regex = NULL;
  GMatchInfo *info = NULL;
  line_regex = g_regex_new("^.*:(\\d+):.*$", 0, 0, NULL);

  for (pointer = split; *pointer; pointer++)
    if (strlen(*pointer)) {
      if (line_regex && g_regex_match(line_regex, *pointer, 0, &info)) {
        if (g_match_info_matches(info)) {
          printf ("info 1 = %4s,   info 0 = %s\n",
              g_match_info_fetch(info, 1),
              g_match_info_fetch(info, 0));
        }
      } else
        printf ("No match in %s\n", *pointer);
    }
  return (0);
}

gtk，正则表达式：如何获取组值

1 个答案: