Question

说我有这个指南：

{2A87E3E2-2B6A-4149-9F5A-1B76092843D9}

它实际上是否在数据库中存储了这个字母数字？（我不这么认为因为它必须适合16个字节。）

如果没有，那么它是如何存储的？（我的猜测是十六进制数，但我不确定。）

如何判断一个GUID是否大于另一个？（Which you may need to know for indexing purposes。）您是否像十六进制数一样读取GUID（用于比较）？

Answer 1

GUID在内部存储为二进制（16）。 MSDN上的"Using uniqueidentifier Data"告诉您这一点。 { }和-不属于该值。

GUID可以“排序”并进行更多/更少的比较：请参阅规范"How are GUIDs sorted by SQL Server?"。

注意：这意味着他们不排序为二进制（16）（除非您认为是CAST ...）

我无法看到为什么你在现实生活中想要这个（不是索引，我的意思是现实世界）：关于NEWID的“排序”潜力的唯一用途是随机的ORDER BY NEWID()

的行技巧

您可以使用NEWSEQUENTIALID获得“升序”GUID（基于上述文章）。但是，在Windows重启=无意义的IMO之后，这种“排序”不会继续。

Answer 2

Necromancing。
GUID存储为字节数组，即二进制（16）您也可以将其存储为UInt128或两个bigint。

关于如何对GUID进行排序：
代码说明了自己，神奇的部分是

System.Guid g
g.ToByteArray();
int[] m_byteOrder = new int[16] // 16 Bytes = 128 Bit 
    {10, 11, 12, 13, 14, 15, 8, 9, 6, 7, 4, 5, 0, 1, 2, 3};


public int Compare(Guid x, Guid y)
{
    byte byte1, byte2;

    //Swap to the correct order to be compared
    for (int i = 0; i < NUM_BYTES_IN_GUID; i++)
    {
        byte1 = x.ToByteArray()[m_byteOrder[i]];
        byte2 = y.ToByteArray()[m_byteOrder[i]];
        if (byte1 != byte2)
            return (byte1 < byte2) ? (int)EComparison.LT : (int)EComparison.GT;
    } // Next i 

    return (int)EComparison.EQ;
}

完整代码：

namespace BlueMine.Data
{


    public class SqlGuid
        : System.IComparable
        , System.IComparable<SqlGuid>
        , System.Collections.Generic.IComparer<SqlGuid>
        , System.IEquatable<SqlGuid>
    {
        private const int NUM_BYTES_IN_GUID = 16;

        // Comparison orders.
        private static readonly int[] m_byteOrder = new int[16] // 16 Bytes = 128 Bit 
        {10, 11, 12, 13, 14, 15, 8, 9, 6, 7, 4, 5, 0, 1, 2, 3};

        private byte[] m_bytes; // the SqlGuid is null if m_value is null


        public SqlGuid(byte[] guidBytes)
        {
            if (guidBytes == null || guidBytes.Length != NUM_BYTES_IN_GUID)
                throw new System.ArgumentException("Invalid array size");

            m_bytes = new byte[NUM_BYTES_IN_GUID];
            guidBytes.CopyTo(m_bytes, 0);
        }


        public SqlGuid(System.Guid g)
        {
            m_bytes = g.ToByteArray();
        }


        public byte[] ToByteArray()
        {
            byte[] ret = new byte[NUM_BYTES_IN_GUID];
            m_bytes.CopyTo(ret, 0);
            return ret;
        }

        int CompareTo(object obj)
        {
            if (obj == null)
                return 1; // https://msdn.microsoft.com/en-us/library/system.icomparable.compareto(v=vs.110).aspx

            System.Type t = obj.GetType();

            if (object.ReferenceEquals(t, typeof(System.DBNull)))
                return 1;

            if (object.ReferenceEquals(t, typeof(SqlGuid)))
            {
                SqlGuid ui = (SqlGuid)obj;
                return this.Compare(this, ui);
            } // End if (object.ReferenceEquals(t, typeof(UInt128)))

            return 1;
        } // End Function CompareTo(object obj)


        int System.IComparable.CompareTo(object obj)
        {
            return this.CompareTo(obj);
        }


        int CompareTo(SqlGuid other)
        {
            return this.Compare(this, other);
        }


        int System.IComparable<SqlGuid>.CompareTo(SqlGuid other)
        {
            return this.Compare(this, other);
        }


        enum EComparison : int
        {
            LT = -1, // itemA precedes itemB in the sort order.
            EQ = 0, // itemA occurs in the same position as itemB in the sort order.
            GT = 1 // itemA follows itemB in the sort order.
        }


        public int Compare(SqlGuid x, SqlGuid y)
        {
            byte byte1, byte2;

            //Swap to the correct order to be compared
            for (int i = 0; i < NUM_BYTES_IN_GUID; i++)
            {
                byte1 = x.m_bytes[m_byteOrder[i]];
                byte2 = y.m_bytes[m_byteOrder[i]];
                if (byte1 != byte2)
                    return (byte1 < byte2) ? (int)EComparison.LT : (int)EComparison.GT;
            } // Next i 

            return (int)EComparison.EQ;
        }


        int System.Collections.Generic.IComparer<SqlGuid>.Compare(SqlGuid x, SqlGuid y)
        {
            return this.Compare(x, y);
        }


        public bool Equals(SqlGuid other)
        {
            return Compare(this, other) == 0;
        }


        bool System.IEquatable<SqlGuid>.Equals(SqlGuid other)
        {
            return this.Equals(other);
        }


    }


}

如何在SQL Server中实际存储和排序/比较guid？

2 个答案: