我的查询
SELECT table1.name, table2.wage, table2.bonus table3.shift, table4.vacation
FROM table1
INNER JOIN table2 ON table1.userid = table2.userid
INNER JOIN table3 ON table2.userid = table3.userid
INNER JOIN table4 ON table4.userid = table4.userid
LEFT JOIN table5 ON table1.name = table5.position
**LEFT JOIN vacation on vacation.userid = table1.userid
WHERE vacation.userid IS NULL**;
这将选择所有userid不在假期表中的地方。
现在我需要检查用户ID是否在假期表中,以及此vacation.status = 1
的{{1}}是否仍应在查询中显示。
答案 0 :(得分:1)
如果这是一个单独的查询/要求,则以下查询将起作用:
SELECT table1.name, table2.wage, table2.bonus table3.shift, table4.vacation
FROM table1
INNER JOIN table2 ON table1.userid = table2.userid
INNER JOIN table3 ON table2.userid = table3.userid
INNER JOIN table4 ON table4.userid = table4.userid
INNER JOIN vacation on vacation.userid = table1.userid
LEFT JOIN table5 ON table1.name = table5.position
WHERE vacation.status = 1;
如果您需要两个要求(userid为NULL或status = 1),请尝试:
SELECT table1.name, table2.wage, table2.bonus table3.shift, table4.vacation
FROM table1
INNER JOIN table2 ON table1.userid = table2.userid
INNER JOIN table3 ON table2.userid = table3.userid
INNER JOIN table4 ON table4.userid = table4.userid
LEFT JOIN table5 ON table1.name = table5.position
LEFT JOIN vacation on vacation.userid = table1.userid
WHERE vacation.user_id IS NULL or vacation.status = 1;