Question

我正试图拉2个数字。一个是总共有多少医生（博士表）在1个月内有超过10个答案（答案表），总共75个答案，无论日期如何。另一个数字是相同的，但是在最近3个月内而不是1个月。

我使用下面的this answer回答来提出此查询：

SELECT D.name, 
    count(DISTINCT case when A.created > DATE_SUB(NOW(), INTERVAL 1 MONTH) then A.id end) as '1 month', 
    count(DISTINCT case when A.created > DATE_SUB(NOW(), INTERVAL 3 MONTH) then A.id end) as '1 quarter', 
    count(DISTINCT A.id) as total
FROM dr D
JOIN answer A ON A.dr_id=D.id AND A.status=3
GROUP BY D.id

这给了我需要的原始信息，但我不知道如何通过将它们与10和75答案要求进行比较来计算给出的计数。

Answer 1

您可能需要稍微玩一下这个查询，但它应该可以为您提供所需的内容。基本上采用您的查询并将其用作派生表，并使用group by / having进一步汇总。

;with DrCounts as (
    SELECT D.id, 
      count(DISTINCT case when A.created > DATE_SUB(NOW(), INTERVAL 1 MONTH) then A.id end) as '1month', 
      count(DISTINCT case when A.created > DATE_SUB(NOW(), INTERVAL 3 MONTH) then A.id end) as '1quarter', 
      count(DISTINCT A.id) as total
    FROM dr D
    JOIN answer A ON A.dr_id=D.id AND A.status=3
    GROUP BY D.id)

select count(distinct D.id) as Dr1075
from  DrCounts D
group by D.Id
having D.total >= 75 and D.1month >= 10
union
select count(distinct D.id) as Dr1075
from  DrCounts D
group by D.Id
having D.total >= 75 and D.1quarter >= 10

Answer 2

这样的事情，我想：

SELECT
  COUNT(CASE WHEN total >= 75 AND `1month`   > 10 THEN name END) AS `10+ per month count`,
  COUNT(CASE WHEN total >= 75 AND `1quarter` > 10 THEN name END) AS `10+ per quarter count`
FROM (
  SELECT D.name, 
    count(DISTINCT case when A.created > DATE_SUB(NOW(), INTERVAL 1 MONTH) then A.id end) as `1month`, 
    count(DISTINCT case when A.created > DATE_SUB(NOW(), INTERVAL 3 MONTH) then A.id end) as `1quarter`, 
    count(DISTINCT A.id) as total
  FROM dr D
    JOIN answer A ON A.dr_id=D.id AND A.status=3
  GROUP BY D.id
) s

计算另一个计数值，但前提是它足够高

2 个答案: