我有一个看起来像这样的文本文件:
gene1 gene2 gene3
a d c
b e d
c f g
d g
h
i
(每列都是一个人类基因,每个都包含可变数量的蛋白质(字符串,在这里显示为字母),可以与这些基因结合)。
我想要做的是计算每个字符串表示的列数,输出该数字和所有列标题,如下所示:
a 1 gene1
b 1 gene1
c 2 gene1 gene3
d 3 gene1 gene2 gene3
e 1 gene2
f 1 gene2
g 2 gene2 gene3
h 1 gene2
i 1 gene2
我一直试图弄清楚如何在Perl和R中做到这一点,但到目前为止还没有成功。谢谢你的帮助。
答案 0 :(得分:8)
这个解决方案似乎有点像黑客,但它提供了所需的输出。它依赖于同时使用plyr
和reshape
包,但我确信你可以找到基本的R替代品。诀窍在于函数melt
允许我们将数据展平为长格式,从而允许从那一点开始轻松(ish)操作。
library(reshape)
library(plyr)
#Recreate your data
dat <- data.frame(gene1 = c(letters[1:4], NA, NA),
gene2 = letters[4:9],
gene3 = c("c", "d", "g", NA, NA, NA)
)
#Melt the data. You'll need to update this if you have more columns
dat.m <- melt(dat, measure.vars = 1:3)
#Tabulate counts
counts <- as.data.frame(table(dat.m$value))
#I'm not sure what to call this column since it's a smooshing of column names
otherColumn <- ddply(dat.m, "value", function(x) paste(x$variable, collapse = " "))
#Merge the two together. You could fix the column names above, or just deal with it here
merge(counts, otherColumn, by.x = "Var1", by.y = "value")
给出:
> merge(counts, otherColumn, by.x = "Var1", by.y = "value")
Var1 Freq V1
1 a 1 gene1
2 b 1 gene1
3 c 2 gene1 gene3
4 d 3 gene1 gene2 gene3
....
答案 1 :(得分:6)
在perl中,假设每列中的蛋白质没有需要去除的重复。 (如果他们这样做,则应该使用散列哈希值。)
use strict;
use warnings;
my $header = <>;
my %column_genes;
while ($header =~ /(\S+)/g) {
$column_genes{$-[1]} = "$1";
}
my %proteins;
while (my $line = <>) {
while ($line =~ /(\S+)/g) {
if (exists $column_genes{$-[1]}) {
push @{ $proteins{$1} }, $column_genes{$-[1]};
}
else {
warn "line $. column $-[1] unexpected protein $1 ignored\n";
}
}
}
for my $protein (sort keys %proteins) {
print join("\t",
$protein,
scalar @{ $proteins{$protein} },
join(' ', sort @{ $proteins{$protein} } )
), "\n";
}
从stdin读取,写入stdout。
答案 2 :(得分:5)
一个衬里(或更确切地说是3个衬里)
ddply(na.omit(melt(dat, m = 1:3)), .(value), summarize,
len = length(variable),
var = paste(variable, collapse = " "))
答案 3 :(得分:1)
如果不是很多列,你可以在sql中做这样的事情。您基本上将数据压缩成2列衍生的蛋白质/基因表,然后根据需要进行总结。
;with cte as (
select gene1 as protein, 'gene1' as gene
union select gene2 as protein, 'gene2' as gene
union select gene3 as protein, 'gene3' as gene
)
select protein, count(*) as cnt, group_concat(gene) as gene
from cte
group by protein
答案 4 :(得分:1)
在mysql中,像这样:
select protein, count(*), group_concat(gene order by gene separator ' ') from gene_protein group by protein;
假设数据如下:
create table gene_protein (gene varchar(255) not null, protein varchar(255) not null);
insert into gene_protein values ('gene1','a'),('gene1','b'),('gene1','c'),('gene1','d');
insert into gene_protein values ('gene2','d'),('gene2','e'),('gene2','f'),('gene2','g'),('gene2','h'),('gene2','i');
insert into gene_protein values ('gene3','c'),('gene3','d'),('gene3','g');