POST请求(Javascript)

时间:2009-03-28 04:30:36

标签: javascript html post

如何在不使用表单且没有回发的情况下在Javascript中发出简单的POST请求?

3 个答案:

答案 0 :(得分:17)

虽然我从@sundeep回答中获取代码示例,但是为了完整性而在此处发布代码

var url = "sample-url.php";
var params = "lorem=ipsum&name=alpha";
var xhr = new XMLHttpRequest();
xhr.open("POST", url, true);

//Send the proper header information along with the request
xhr.setRequestHeader("Content-type", "application/x-www-form-urlencoded");

xhr.send(params);

答案 1 :(得分:5)

我创建的功能是发送请求而不刷新页面,而不打开页面,没有AJAX 。进程对用户是不可见的。我使用假iframe发送请求:

/**
* Make a request without ajax and without refresh the page
* Invisible for the user
* @param url string
* @param params object
* @param method string get or post
**/
function requestWithoutAjax( url, params, method ){

    params = params || {};
    method = method || "post";

    // function to remove the iframe
    var removeIframe = function( iframe ){
        iframe.parentElement.removeChild(iframe);
    };

    // make a iframe...
    var iframe = document.createElement('iframe');
    iframe.style.display = 'none';

    iframe.onload = function(){
        var iframeDoc = this.contentWindow.document;

        // Make a invisible form
        var form = iframeDoc.createElement('form');
        form.method = method;
        form.action = url;
        iframeDoc.body.appendChild(form);

        // pass the parameters
        for( var name in params ){
            var input = iframeDoc.createElement('input');
            input.type = 'hidden';
            input.name = name;
            input.value = params[name];
            form.appendChild(input);
        }

        form.submit();
        // remove the iframe
        setTimeout( function(){ 
            removeIframe(iframe);
        }, 500);
    };

    document.body.appendChild(iframe);
}

现在你可以做到:

requestWithoutAjax('url/to', { id: 2, price: 2.5, lastname: 'Gamez'});

看看它是如何运作的!:http://jsfiddle.net/b87pzbye/10/

答案 2 :(得分:3)

您可以使用AJAX调用(XMLHttpRequest对象)

来完成此操作

http://www.openjs.com/articles/ajax_xmlhttp_using_post.php