我想访问数据并在标签中显示ajax页面方法但数据未显示。
PageMethods.GetDataFromDB(OnSucceeded, OnFailed);
//}
function OnSucceeded(result, userContext, methodName) {
var jsonData = eval(result.d);
$get('Label1').innerHTML = jsonData.FirstName;
}
[WebMethod]
public static string GetDataFromDB()
{
System.Collections.Generic.Dictionary<string, string> DictionaryGetPerson = new Dictionary<string, string>();
using (OracleConnection con = new OracleConnection("server=xe; uid=system; pwd=;"))
{
string Command = "Select * from tblSavePerson"; //selecting Top 1 Row in Oracle
OracleCommand cmd = new OracleCommand(Command, con);
con.Open();
OracleDataReader dr = cmd.ExecuteReader();
while (dr.Read())
{
DictionaryGetPerson.Add("FirstName",dr["FirstName"].ToString());
}
}
JavaScriptSerializer js = new JavaScriptSerializer();
return js.Serialize(DictionaryGetPerson).ToString();
}
表只有一行。
答案 0 :(得分:0)
由于你已经将标签作为jQuery和jQuery Ajax给出了,我与解决方案略有不同。
做这些事
1.将WebMethod
包裹在try-catch块中。 try-catch是有原因的。
[WebMethod]
public static string GetDataFromDB()
{
try
{
System.Collections.Generic.Dictionary<string, string> DictionaryGetPerson = new Dictionary<string, string>();
using (OracleConnection con = new OracleConnection("server=xe; uid=system; pwd=;"))
{
string Command = "Select * from tblSavePerson"; //selecting Top 1 Row in Oracle
OracleCommand cmd = new OracleCommand(Command, con);
con.Open();
OracleDataReader dr = cmd.ExecuteReader();
while (dr.Read())
{
DictionaryGetPerson.Add("FirstName", dr["FirstName"].ToString());
}
}
JavaScriptSerializer js = new JavaScriptSerializer();
return js.Serialize(DictionaryGetPerson).ToString();
}
catch (Exception exception)
{
//Elmah.ErrorSignal.FromCurrentContext().Raise(exception);
throw new Exception(exception.Message);
}
}
请注意,如果您有多行,此词典将失败并显示重复键错误。如果没有错误,请转到步骤2.
2.不要使用 。它非常古老。 Using jQuery one can consume ASP.NET Ajax Page Methods directly。像这样调用页面方法。PageMethods.GetDataFromDB
function LoadNames() {
$.ajax({
contentType: "application/json;",
data: "{}",
type: "POST",
url: 'Test1.aspx/GetDataFromDB',
success: function (msg) {
OnSucceeded(msg);
},
error: function (xhr, status, error) {
//alert("error");
//OnFailed(a, b, c);
}
});
}
function OnSucceeded(dict) {
var jsonData = dict.hasOwnProperty("d") ? dict.d : dict;
var json = $.parseJSON(jsonData);
alert(json.FirstName);
}
另外,当我们在jQuery中有eval(result.d)
时,请不要 。$.parseJSON
希望这有帮助。