在FormView form_valid方法中更新上下文数据?

时间:2011-08-02 04:50:43

标签: python django django-class-based-views

我有一个类QuestionView,它派生自FormView类。这里 是一个解释我的问题的代码片段:

class QuestionView(FormView):
    ...
    context_var1 = y
    def form_valid (self, form):
    ...
    self.context_var1 = x
    ...
    def get_context_data(self, **kwargs):
    ...
    context['context_var1'] = self.context_var1
    ...
    return context

如上所示,我在form_valid和更新中更新了一组上下文变量 我打算在模板中使用这些更新的值 - 因此context字典中的变量。这段代码的问题在于改变了 未见context_var1 - 可能是因为get_context_dataform_valid方法之前调用。是否有解决方法 此?

4 个答案:

答案 0 :(得分:25)

我使用form_invalid执行此操作。我是这样做的:

from django.views.generic import FormView

class ContextFormView(FormView):
    def get(self, request, *args, **kwargs):
        form_class = self.get_form_class()
        form = self.get_form(form_class)
        context = self.get_context_data(**kwargs)
        context['form'] = form
        return self.render_to_response(context)

    def post(self, request, *args, **kwargs):
        form_class = self.get_form_class()
        form = self.get_form(form_class)
        if form.is_valid():
            return self.form_valid(form)
        else:
            return self.form_invalid(form, **kwargs)

    def form_invalid(self, form, **kwargs):
        context = self.get_context_data(**kwargs)
        context['form'] = form
        return self.render_to_response(context)

你可以做同样的事情,但是对于form_valid。通常,form_valid的主体如下所示:

def form_valid(self, form):
    return HttpResponseRedirect(self.get_success_url())

您必须同时覆盖postform_valid,因为post会调用form_valid

def post(self, request, *args, **kwargs):
    form_class = self.get_form_class()
    form = self.get_form(form_class)
    if form.is_valid():
        return self.form_valid(form, **kwargs)
    else:
        return self.form_invalid(form, **kwargs)

def form_valid(self, form, **kwargs):
    # take some other action here
    return HttpResponseRedirect(self.get_success_url())

哦,只是为了澄清,存在此问题的原因是ProcessFormView类的get方法被破坏了。通常看起来像这样:

def get(self, request, *args, **kwargs):
    form_class = self.get_form_class()
    form = self.get_form(form_class)
    return self.render_to_response(self.get_context_data(form=form))

它只是把kwargs扔掉了(._.)

答案 1 :(得分:5)

在Django 2.0.1中,您可以通过覆盖Messageget_context_data来插入上下文数据。

在您的情况下,您可以执行以下某项覆盖:

form_invalid

或者:

class QuestionView(FormView):
    ...

    def form_invalid(self, form):
        """If the form is invalid, render the invalid form."""
        return self.render_to_response(
            self.get_context_data(
                form=form, 
                context_key=some_value
            )
        )

Django 2.0.1将表单插入到class QuestionView(FormView): ... def get_context_data(self, **kwargs): if 'context_key' not in kwargs: # set value if not present kwargs['context_key'] = some_value return super().get_context_data(**kwargs) 的kwargs中。

get_context_data

答案 2 :(得分:1)

在views.py

class UploadTest(FormView):
    template_name = 'test.html'
    ....
    plus_context = dict()

    def form_valid(self, form):
        ...
        self.plus_context['you_want_context'] = value
        ...
        return super(UploadTest, self).form_valid(form)

    def get_context_data(self, **kwargs):
        context = super(UploadTest, self).get_context_data(**kwargs)
        context['plus_context_key'] = self.plus_context
        return context

在test.html中

<html>
    ....
    <body>
    ....
    // first post can not get plus_context_key
    {% if plus_context_key %}
        {{ plus_context_key.you_want_context }}
    {% endif %}    
    </body>
</html>

我只是在Django 1.10.3中找到了这个方法。 希望可以帮到你

答案 3 :(得分:0)

也许你可以使用这种方法:

class SomeView(View):

    def post(self, request):
        my_form = MyForm(request.POST)
        if my_form.is_valid():
            context['foo'] = 'bar'

        return render(request, 'valid/path.html', context)