Question

我需要从查询中返回的是过去一年访问过的家庭户主及其所有亲属的名单。每个人都在Client表中，在查询时它连接到其他表。

问题是查询为每个唯一的DateVisited返回一组Family成员。我希望得到一组看起来像这样的结果（为了清楚起见，我省略了一些列）：

Head of household                Relative/child
----------------------------     ---------------------
John Smith -                     Katie Smith
John Smith                       Joe Smith
Tim Jones                        Mike Jones
Tim Jones                        Sally Jones
Kevin Barnett                    Corey Barnett
Kevin Barnett                    Cara Barnett
Kevin Barnett                    Austin Barnett




SELECT f.HeadOfHouseholdID,
  CONCAT( c.lastname,  ', ', c.firstname ) AS  'HName',
  v.Datevisited, f.RelationshipID, c2.ClientID,
  CONCAT( c2.lastname,  ', ', c2.firstname ) AS  'Relative Name'
FROM client c
INNER JOIN clientfamily f ON c.ClientID = f.HeadOfHouseholdID
JOIN visits v ON c.clientid = v.clientID
JOIN client c2 ON c2.clientid = f.relativeID
WHERE v.datevisited BETWEEN CURDATE( ) - INTERVAL 1 YEAR AND CURDATE( )

！[查询结果] [1]

Answer 1

一位同事想通了：

SELECT f.HeadOfHouseholdID 'HOHID',
    CONCAT( c.Lastname, ', ', c.FirstName ) AS 'Head of Household',
    c.PhoneNumber AS 'HOH Phone',
    f.RelativeID,
    CONCAT( C2.Lastname, ', ', C2.FirstName ) AS 'Relative',
    Relationship.Description AS 'Relation',
    C2.PhoneNumber AS 'Relative Phone', C2.DOB,
    (
            (
            DATE_FORMAT( NOW( ) , '%Y' ) - DATE_FORMAT( C2.DOB, '%Y' )
            ) -
            ( DATE_FORMAT( NOW( ) , '00-%m-%d' ) < DATE_FORMAT( C2.DOB, '00-%m-%d' ) )
    ) AS Age
    FROM client c
    INNER JOIN clientfamily f ON c.clientid = f.headofhouseholdid
    JOIN (
            SELECT ClientID, MAX( DateVisited ) AS 'DateVisited'
            FROM Visits
            GROUP BY ClientID
    ) v ON c.clientid = v.clientid
    JOIN client c2 ON c2.clientid = f.relativeid
    JOIN Relationship ON f.RelationshipID = Relationship.RelationshipID
    WHERE v.datevisited
            BETWEEN CURDATE( ) - INTERVAL 1 YEAR
            AND CURDATE( )

在MySQL中选择1个客户家庭实例

1 个答案: