我想比较2个JavaScript对象的类。以下当前通话失败。这里的想法是使用传入的“从和到”变量来提取正确的交叉率。
感谢您的帮助!
更新:工作代码现在看起来像这样:
<script type="text/javascript">
<!--
// ------------------------
// CLASS
function Currency(clientId, country, code, imageURL, name) {
this.clientId = clientId //EXAMPLE: txtBudget
this.country = country; //EXAMPLE: America
this.code = code; //EXAMPLE: USD
this.imageURL = imageURL; //EXAMPLE: "http://someplace/mySymbol.gif"
this.name = name; //EXAMPLE: Dollar
this.amount = parseFloat("0.00"); //EXAMPLE: 100
};
Currency.prototype.convertFrom = function (currency, factor) {
this.amount = currency.amount * factor;
}
// CLASS
function Pound(clientId, imageURL) {
Currency.call(this, clientId, "Greate Britain", "GBP", imageURL, "Pound");
};
Pound.prototype = new Currency();
Pound.prototype.constructor = Pound;
// CLASS
function Dollar(clientId, imageURL) {
Currency.call(this, clientId, "America", "USD", imageURL, "Dollar");
};
Dollar.prototype = new Currency();
Dollar.prototype.constructor = Dollar;
// CLASS
function Reais(clientId, imageURL) {
Currency.call(this, clientId, "Brazil", "BRL", imageURL, "Reais");
};
Reais.prototype = new Currency();
Reais.prototype.constructor = Reais;
// ------------------------
// CLASS
function Suscriber(element) {
this.element = element;
};
// CLASS
function Publisher() {
this.subscribers = new Array();
this.currencyCrossRates = new Array();
};
Publisher.prototype.findCrossRate = function (from, to) {
var crossRate = null;
for (var i = 0; i < this.currencyCrossRates.length; i++) {
if ((this.currencyCrossRates[i].from.constructor === from.constructor) && (this.currencyCrossRates[i].to.constructor === to.constructor))
crossRate = this.currencyCrossRates[i];
}
return crossRate;
}
// ------------------------
// CLASS
function CurrencyCrossRate(from, to, rate) {
this.from = from;
this.to = to;
this.rate = parseFloat(rate);
};
jQuery(document).ready(function () {
var dollar = new Dollar(null, null);
var reais = new Reais(null, null);
var dollarToReais = new CurrencyCrossRate(dollar, reais, 0.8);
var reaisToDollar = new CurrencyCrossRate(reais, dollar, 1.2);
publisher = new Publisher();
publisher.currencyCrossRates.push(dollarToReais);
publisher.currencyCrossRates.push(reaisToDollar);
// SETUP
jQuery(".currency").each(function () {
publisher.subscribers.push(new Suscriber(this));
});
var newDollar = new Dollar(null, null);
var newReais = new Reais(null, null);
// This now resolves correctly
var first = crossRate = publisher.findCrossRate(newDollar, newReais);
var second = crossRate = publisher.findCrossRate(newReais, newDollar);
});
-->
</script>
答案 0 :(得分:2)
instanceof
的右侧操作符不应该是原型对象,而是对象的构造函数,可以通过相关对象的constructor
属性访问。由于此属性实际上引用了用于构造对象的 函数,因此使用通常的相等运算符进行比较:
this.currencyCrossRates[i].from.constructor == from.constructor
编辑:
删除行Pound.prototype.constructor = Pound();
等(每种货币一行)。 constructor
属性是一个内置功能,可自动引用正确的功能。但是, 不幸是可写的,因此可以重新分配 - 不要这样做!
条件应为this.currencyCrossRates[i].from instanceof from.constructor
形式 - 左操作数是对象,右边是构造函数函数。