Question

我试着寻找我需要的东西但是我没有成功。

我正在从webservice读取XML字符串，我需要将我的信息存储到核心数据中。我必须从Department开始排序，它指向所选部门中的所有子部门，然后当选择子部门时，它将列出该子部门中的所有项目。这个问题是我收到了数据表中的所有信息，因此它有部门和子部门的重复。因此，为了对它进行排序，我想将信息存储到我有一个字典数组的位置，每个字典包含每个部门的名称，然后是一个字典数组，其中包含每个子部门的名称，然后是另一个字典数组所有项目信息。

我需要它像下面这样......

部门词典数组
1. 部门词典
  1. 持有部门名称的字符串
  2. 子部门词典数组
    1. 子部门词典
      1. 持有子部门名称的字符串
      2. 项目词典数组
        
        项目词典
        
        持有项目名称的字符串
        
        持有更多项目信息的字符串

（对不起，我不知道如何以任何其他方式表达......）

XML代码示例：

        <QSR_VIEWS_INVENTORY_ITEMS_LIST diffgr:id="QSR_VIEWS_INVENTORY_ITEMS_LIST1" msdata:rowOrder="0"><CompanyID>104</CompanyID><QSRInventoryItemID>111</QSRInventoryItemID><Description>Test Item 111</Description><Department>_</Department><Subdepartment>_</Subdepartment><SequenceNumber>0</SequenceNumber><CountDisplayUnitName>CA</CountDisplayUnitName><CountDisplayUnitInCase>1.0000</CountDisplayUnitInCase><ReorderAt>0.0000</ReorderAt><ReorderTo>0.0000</ReorderTo><CaseUnitName>CA</CaseUnitName><CaseInCase>1.0000</CaseInCase><PackUnitName>_</PackUnitName><PacksInCase>0.0000</PacksInCase><StackUnitName>_</StackUnitName><StacksInCase>0.0000</StacksInCase><EachUnitName>_</EachUnitName><EachInCase>0.0000</EachInCase><InLocation1>N</InLocation1><InLocation2>N</InLocation2><InLocation3>N</InLocation3><InLocation4>N</InLocation4><InLocation5>N</InLocation5><InLocation6>N</InLocation6><InLocation7>N</InLocation7><InLocation8>N</InLocation8><InLocation9>N</InLocation9><InLocation10>N</InLocation10><InLocation11>N</InLocation11><InLocation12>N</InLocation12><InLocation13>N</InLocation13><InLocation14>N</InLocation14><InLocation15>N</InLocation15><OnShiftCountSheet>Y</OnShiftCountSheet><OnDayCountSheet>Y</OnDayCountSheet><OnWeekCountSheet>Y</OnWeekCountSheet><OnMonthCountSheet>Y</OnMonthCountSheet><OnWasteCountSheet>Y</OnWasteCountSheet><EquivalentToItemID>0</EquivalentToItemID><EquivalentCaseFactor>0.0000</EquivalentCaseFactor></QSR_VIEWS_INVENTORY_ITEMS_LIST>

Answer 1

我认为您需要的是一个额外的字典，其中包含所有单个部门和子部门的密钥，然后您使用该字典检查您是否已经拥有新部门，如果不是，在适当的地方创建它。内存开销应该可以忽略不计，额外的字典只会指向现有对象。

Answer 2

Answer provided by Alex Mayfield：

注意：有可能比我做的更好的方法。

BOOL addI = YES;
BOOL addS = YES;
BOOL addD = YES;
int I;
int S;
int D;

for(int i = 0;  i < [DArray count]; i++)
{
    DDictionary = [DArray objectAtIndex:i];
    //NSLog([NSString stringWithFormat:@"%@ vs %@", soapResults12, [DDictionary objectForKey:@"Title"]]);
    if([soapResults12 isEqualToString:[DDictionary objectForKey:@"Title"]])
    {
        D = i;
        //NSLog(@"GOT IT");
        SArray = [DDictionary objectForKey:@"Subdepartments"];
        for(int k = 0; k < [SArray count]; k++)
        {
            SDictionary = [SArray objectAtIndex:k];
            soapResults11 = [soapResults11 stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
            //NSLog([NSString stringWithFormat:@"%@ vs %@", soapResults11, [SDictionary objectForKey:@"Title"]]);
            if([soapResults11 isEqualToString:[SDictionary objectForKey:@"Title"]])
            {
                S = k;
                //NSLog(@"GOT IT");
                IArray = [SDictionary objectForKey:@"Items"];
                for(int r = 0; r < [IArray count]; r++)
                {
                    IDictionary = [IArray objectAtIndex:r];
                    //NSLog([NSString stringWithFormat:@"%@ vs %@", soapResults1, [IDictionary objectForKey:@"Title"]]);
                    if([soapResults1 isEqualToString: [IDictionary objectForKey:@"Title"]])
                    {
                        //NSLog(@"GOT IT");
                        I = r;
                        r = [IArray count];
                        addI = NO;
                        addS = NO;
                        addD = NO;
                    }
                    else
                    {
                        addI = YES;
                        addS = NO;
                        addD = NO;
                    }

                }
                k = [SArray count];

            }
            else
            {

                addS = YES;
                addD = NO;
            }

        }
        i = [DArray count];

    }
    else
    {

        addD = YES;
    }

}
if(addI && !addS && !addD)
{                        
    IDictionary = [[NSMutableDictionary alloc] init];
    [IDictionary setObject:soapResults1 forKey:@"Title"];
    [IArray addObject:IDictionary];
    [SDictionary setObject:IArray forKey:@"Items"];
    [SArray replaceObjectAtIndex:S withObject:SDictionary];
    [DDictionary setObject:SArray forKey:@"Subdepartments"];
    [DArray replaceObjectAtIndex:D withObject:DDictionary];
}
if(addS && !addD)
{
    IDictionary = [[NSMutableDictionary alloc] init];
    IArray = [[NSMutableArray alloc] init];
    [IDictionary setObject:soapResults1 forKey:@"Title"];
    [IArray addObject:IDictionary];
    SDictionary = [[NSMutableDictionary alloc] init];
    [SDictionary setObject:soapResults11 forKey:@"Title"];
    [SDictionary setObject:IArray forKey:@"Items"];
    [SArray addObject:SDictionary];
    [DDictionary setObject:SArray forKey:@"Subdepartments"];
    [DArray replaceObjectAtIndex:D withObject:DDictionary];

}    

if(addD)
{
    IDictionary = [[NSMutableDictionary alloc] init];
    IArray = [[NSMutableArray alloc] init];
    [IDictionary setObject:soapResults1 forKey:@"Title"];
    [IArray addObject:IDictionary];
    SDictionary = [[NSMutableDictionary alloc] init];
    SArray = [[NSMutableArray alloc] init];
    [SDictionary setObject:soapResults11 forKey:@"Title"];
    [SDictionary setObject:IArray forKey:@"Items"];
    [SArray addObject:SDictionary];
    DDictionary = [[NSMutableDictionary alloc] init];
    [DDictionary setObject:soapResults12 forKey:@"Title"];
    [DDictionary setObject:SArray forKey:@"Subdepartments"];
    [DArray addObject:DDictionary];
}

存储在NSMutableDictionaries中而不知道会有多少？

2 个答案: