这是我在C#计划中的陈述:
(由gbn编辑,格式清晰,所以 all 在一行上)
DbCommand.CommandText =
@"SELECT
HIST.MBRSEP, HIST.LOCATION, HIST.BILLTYPE, HIST.BILLMOYR, LOCINFO.CYCLE,
LOCINFO.DIST, LOCINFO.LOCATION
FROM
(CAV_MBRHISTDEL AS HIST INNER JOIN CAV_LOCINFODETL AS LOCINFO ON HIST.LOCATION = LOCINFO.LOCATION)
WHERE
LOCINFO.CYCLE = @CYCLE AND
LOCINFO.DIST = @DISTRICT AND
HIST.BILLTYPE = '09' AND
HIST.BILLMOYR <> '9999'";
以下是错误消息:
错误[HY000] [Oracle] [ODBC] [Ora] ORA-00907:缺少右括号
我的SQL语句中只有两个括号,一个是右边的,一个是左边的。我不确定错误告诉我的是什么。有什么建议吗?
编辑:以下是参数的定义方式:
string cycle = cbCycle.Text;
string district = cbDistrict.Text.Substring(0,2);
这是我将它们添加到DbCommand的地方:
DbCommand.Parameters.AddWithValue("@CYCLE", cycle);
DbCommand.Parameters.AddWithValue("@DISTRICT", district);
这是我的完整代码,当有人点击表单上的“转到”按钮时会触发该代码:
private void btnGo_Click(object sender, EventArgs e)
{
//get parameters
string cycle = cbCycle.Text;
string district = cbDistrict.Text.Substring(0,2);
//create a connection to the database
OdbcConnection DbConnection = new OdbcConnection("DSN=UPN2;uid=xxx;pwd=xxxx");
DbConnection.Open();
//create a command to extract the required data and
//assign it to the connection string
OdbcCommand DbCommand = DbConnection.CreateCommand();
DbCommand.CommandText =
@"SELECT HIST.MBRSEP, HIST.LOCATION, HIST.BILLTYPE, HIST.BILLMOYR, LOCINFO.CYCLE, LOCINFO.DIST, LOCINFO.LOCATION FROM CAV_MBRHISTDEL AS HIST INNER JOIN CAV_LOCINFODETL AS LOCINFO ON HIST.LOCATION = LOCINFO.LOCATION WHERE LOCINFO.CYCLE = @CYCLE AND LOCINFO.DIST = @DISTRICT AND HIST.BILLTYPE = '09' AND HIST.BILLMOYR <> '9999'; ";
DbCommand.Parameters.AddWithValue("@CYCLE", cycle);
DbCommand.Parameters.AddWithValue("@DISTRICT", district);
//Create a DataAdapter to run the command and fill the datatable
OdbcDataAdapter da = new OdbcDataAdapter();
da.SelectCommand = DbCommand;
DataTable dt = new DataTable();
da.Fill(dt);
tbOutput.Text = PrintDataTable(dt);
DbCommand.Dispose();
DbConnection.Close();
}
答案 0 :(得分:3)
尝试删除您拥有的括号:您不需要它们。
答案 1 :(得分:3)
问题可能是您使用oracle保留字作为列名和param名称 - 即CYCLE
...
这样做可能会导致DB的奇怪和不稳定的行为!
请参阅http://download.oracle.com/docs/cd/B19306_01/em.102/b40103/app_oracle_reserved_words.htm
根据您的数据库提供程序的不同,您可能希望使用:
代替@
来获取参数。
答案 2 :(得分:1)
您错过了内部查询中的SELECT
。试试这个:
...
FROM
(SELECT CAV_MBRHISTDEL AS HIST -- Added SELECT
INNER JOIN CAV_LOCINFODETL AS LOCINFO ON HIST.LOCATION = LOCINFO.LOCATION)
WHERE
...
你有:
FROM
(CAV_MBRHISTDEL ... -- Missing SELECT