Question

我有一个MySQL表，其中有一个payment_date行。我从日期X和日期Y获取行。我想打印每个日期的出现次数。

例如：

payment_date
2011-07-25
2011-07-24
2011-07-25
2011-06-13

我需要将其归还：

2011-07-25 got 2 payments
2011-07-24 got 1 payments
2011-06-13 got 1 payment

有了这个信息，我正在做一个情节，X轴：日期和Y轴：付款次数。

我现在的查询是：

SELECT *
FROM table_pay
WHERE DATE_FORMAT(payment_date, '%m/%d/%Y')
BETWEEN '$payment_date_from'
AND
DATE '$payment_date_to'
GROUP BY DATE(payment_date)

[不知道!!!!]

请帮忙吗？

Answer 1

SELECT 
payment_date,count(*) as tot
FROM table_pay
WHERE payment_date
BETWEEN '$payment_date_from'
AND
'$payment_date_to'
GROUP BY payment_date
order by tot desc

Answer 2

试试这个，现在无法测试，所以请回答它是否按预期工作

SELECT DATE_FORMAT(payment_date, '%Y-%m-%d'), COUNT(*)
FROM table_pay
WHERE payment_date BETWEEN '$payment_date_from' AND '$payment_date_to'
GROUP BY payment_date

Answer 3

我会使用如下的查询（假设payment_date是日期）：

Select payment_date, count(*) as paymentcount from table_pay where payment_date between 'startdate' and 'enddate' group by payment_date

MySQL日期范围：在相同日期之间发生

3 个答案: