<asp:ListView ID="lvGallery" runat="server" DataSourceID="SqlDataSource1">
<LayoutTemplate>
<table runat="server" id="tableGallery">
<tr runat="server" id="itemPlaceHolder">
</tr>
</table>
</LayoutTemplate>
<ItemTemplate>
<tr><td>
<div class="box_img2">
<div class="g_size">
<a runat="server" id="linkImage"><img id="Image1" runat="server" src="MyImage.jpg" /></a>
</div>
</div>
</td></tr>
</ItemTemplate>
</asp:ListView>
<asp:SqlDataSource ID="SqlDataSource1" runat="server"
ConnectionString="Data Source=CHANDAN-PC;Initial Catalog=Metamorphism;User ID=sa;password=chandan;"
ProviderName="System.Data.SqlClient"
SelectCommand="SELECT [Image] FROM [GalleryImages]"></asp:SqlDataSource>
public void ProcessRequest(HttpContext context)
{
//write your handler implementation here.
string username = Convert.ToString(context.Request.QueryString["username"]);
if (username != null)
{
DataSet ds = new DataSet();
SqlDataAdapter da = new SqlDataAdapter();
byte[] arrContent;
DataRow dr;
string strSql;
strSql = "Select Image from GalleryImages where username = '" + username + "'";
da = new SqlDataAdapter(strSql, connection.ConnectionString);
da.Fill(ds);
dr = ds.Tables[0].Rows[0];
arrContent = (byte[])dr["ImageFile"];
context.Response.ContentType = "jpeg";
context.Response.OutputStream.Write(arrContent, 0, arrContent.Length);
context.Response.End();
}
}
我在web.config中添加了httphandlers标记。
答案 0 :(得分:1)
我认为你需要改变这个
<div class="box_img2">
<div class="g_size">
<a runat="server" id="linkImage">
<img id="Image1" runat="server" src='<%# Eval( HttpContext.Current.Request.QueryString["username"] ,"YourGenericHandler.ashx?username={0}") %>' /></a>
</div>
</div>