在红宝石中找到最近的记录

Question

以下代码有效，但看起来并不像红宝石，所以我正在寻找一种更好的方法来实现同样的目标。

#Grab the events from the page 
  events = page.events.sort_by{|e| e.start_time}

  upcoming = []
  past = []

  events.each do |e|
    if e.start_time >= Time.now
      upcoming.push(e)
    end
    if e.start_time < Time.now
      past.push(e)
    end
  end

 # show the most nearest event (current events if exist)
 event_to_show = (upcoming.count < 0) ? upcoming.first : past.last

Answer 1

您可以使用partition方法来简化代码。

http://www.ruby-doc.org/core/classes/Enumerable.html#M001496

events = page.events.sort_by(&:start_time)

upcoming, past = events.partition{|e| e.start_time >= Time.now}

event_to_show = (upcoming.count < 0) ? upcoming.first : past.last