Question

在回调请求表单中遇到一些问题我正在尝试为移动网站构建。基本上问题是我收到了电子邮件，但字段是空的，好像它已被发送而没有输入任何输入字段。显然，PHP抓住我的字段并发布它们肯定存在问题，但我似乎无法弄清楚我做错了什么：

    <?php

$EmailFrom = $_POST['ftEmail'];
// $EmailTo = "me@xxxx.com";
$EmailTo = "me@xxxxx.com";
$Subject = "Call back request from a mobile";
$Name = Trim(stripslashes($_POST['ftName'])); 
$Email = Trim(stripslashes($_POST['ftEmail'])); 
$Tel = Trim(stripslashes($_POST['ftTel'])); 
/* - IF NEED TO CONNECT TO DATABASE
$con = mysql_connect("xxx","xxx","xxx");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }

mysql_select_db("farmpro1_mosuro", $con);

$sql="INSERT INTO contact_form (Name, Tel, Email)
VALUES
('$_POST[Name]','$_POST[Tel]','$_POST[Email]')";

if (!mysql_query($sql,$con))
  {
  die('Error: ' . mysql_error());
  }

*/

// email body text
$Body = "";
$Body .= "Name: ";
$Body .= $Name;
$Body .= "\n";
$Body .= "Email: ";
$Body .= $Email;
$Body .= "\n";
$Body .= "Tel: ";
$Body .= $Tel;
$Body .= "\n";




    // send the email 
    $success = mail($EmailTo, $Subject, $Body, "From: <$EmailFrom>");

    // redirect to thank you page 
    if ($success){
      print "<meta http-equiv=\"refresh\" content=\"0;URL=contact_thanks.php\">";
    }
    else{
      print "<meta http-equiv=\"refresh\" content=\"0;URL=error.html\">";
    }



mysql_close($con)

?>






<form action="send_request_mobile.php">
                        <input type="text" value="ftName" name="ftName" id="ftName"><br>
                        <input type="text" value="ftEmail" name="ftEmail" id="ftEmail"><br>
                        <input type="text" value="ftTel" name="ftTel" id="ftTel">
                        <input type="submit" value="SEND" class="ftSubmit">
</form>

任何帮助都会很棒！

谢谢，

Answer 1

您的表单没有method属性，因此默认为GET，您正在寻找$_POST中的数据。

<form action="send_request_mobile.php" method="post">

发布PHP联系表单的问题

1 个答案: