首先，我有这个问题：
SELECT `a`.`title`, `a`.`askprice`, `a`.`picture`, `a`.`description`, `a`.`userid`,
`a`.`id`
FROM (`mm_ads` AS a)
LEFT JOIN `mm_ads_fields_values` AS afv ON `a`.`id` = `afv`.`aid`
WHERE `a`.`status` = 1
AND `a`.`category` = '230'
AND `a`.`id` IN 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9932,9936,9940,9943,9946,9950,9954,9957,9962,9964,9966,9973,9976,9977,9980,9981,9985,9986,9987,9989,10019,10022,10025,10027,10028,10055,10062,10189,10195,10197,10212,10220,10221,10224,10226,10229,10231,10232,10235,10428,10431,10434,10438,10440,10442,10443,10445,10448,10449,10455,10459,10466,10469,10471,10473,10474,10475,10476,10478,10481,10484,10486,10489,10493,10494,10496,10497,10499,10501,10502,10503,10508,10511,10514,10516,10518,10521,10524,10528,10529,10532,10160,10158,10156,10153,10149,10146,10138,10133,10132,10129,10126,10123,10119,10117,10116,10112,10111,10109,10101,10099,10097,10093,10090,10086,10084,10082,10078,10074,10070,10066,10045,10052,10041,10037,10036,10033,18596)
AND `a`.`userid` = '136'
GROUP BY `a`.`id`
ORDER BY `id` DESC, `id` DESC
LIMIT 15;
我需要把它改成这个：
当前查询：
SELECT a.title, a.askprice, a.picture, a.description, a.userid, a.id FROM
(SELECT aid FROM mm_ads_fields_values afv WHERE value = '2913' OR value = '3022' GROUP BY aid HAVING COUNT(*) = 2 ) af
JOIN mm_ads AS a ON (a.id = af.aid) WHERE a.category = 227 AND a.status = 1 ORDER BY askprice DESC LIMIT 0,20
查询会生成所有“宝马”和“黑色”的汽车。
更新
mm_ads：广告存储在
中的表格mm_ads_fields_values：存储广告选项的表格。
示例：Car是ad并且在表mm_ads中有一行。汽车有以下选项：品牌，型号，颜色......所以汽车广告在表mm_ads_fields_values中有多行。
更新2：
2913表示“黑色”颜色选项
3022表示“宝马”品牌选项
我需要添加3020，这意味着“灰色”颜色选项
问题：
如果我想获得“宝马”和（“黑色”或“灰色”）汽车怎么办？查询怎么样？
答案 0 :(得分：3)
查询中的静态值很难处理（a.category值为227表示黑色吗？）但实际上，您可以使用：
WHERE color in ('black','gray')
答案 1 :(得分：0)
我找到了解决方案。
MySQL查询：
SELECT a.title, a.askprice, a.picture, a.description,
a.userid, a.id
FROM mm_ads AS a
JOIN mm_ads_fields_values v1 ON v1.aid = a.id AND v1.value = '2913'
JOIN mm_ads_fields_values v2 ON v2.aid = a.id AND v2.value IN ("3022","3020")
WHERE a.category = 227
AND a.status = 1
ORDER BY askprice DESC