例如今天是28/07/2011 我如何在星期一的第一天获得星期五,即2011年7月25日在红宝石
答案 0 :(得分:32)
>> Date.today.beginning_of_week.strftime('%d/%m/%Y')
#=> 25/07/2011
答案 1 :(得分:26)
没有Rails / ActiveSupport:
phrogz$ irb
> require 'date'
> now = Date.today
#=> #<Date: 2011-07-28 (4911541/2,0,2299161)>
> sunday = now - now.wday
#=> #<Date: 2011-07-24 (4911533/2,0,2299161)>
> monday = now - (now.wday - 1) % 7
#=> #<Date: 2011-07-25 (4911535/2,0,2299161)>
> monday.iso8601
#=> "2011-07-25"
> monday.strftime('%d/%m/%Y')
#=> "25/07/2011"
有关详情,请参阅标准库中的Date
课程。
作为一种方法包装:
require 'date'
# For weekdays to start on Monday use 1 for the offset; for Tuesday use 2, etc.
def week_start( date, offset_from_sunday=0 )
date - (date.wday - offset_from_sunday)%7
end
sun = Date.parse '2011-07-24'
week_start(sun,0).strftime('%a, %b-%d') #=> "Sun, Jul-24"
week_start(sun,1).strftime('%a, %b-%d') #=> "Mon, Jul-18"