我有以下代码段。
$items['A'] = "Test";
$items['B'] = "Test";
$items['C'] = "Test";
$items['D'] = "Test";
$index = 0;
foreach($items as $key => $value)
{
echo "$index is a $key containing $value\n";
$index++;
}
预期产出:
0 is a A containing Test
1 is a B containing Test
2 is a C containing Test
3 is a D containing Test
有没有办法省略$index
变量?
答案 0 :(得分:14)
你的$ index变量有点误导。这个数字不是索引,你的“A”,“B”,“C”,“D”键都是。您仍然可以通过编号索引$ index [1]访问数据,但这不是重点。如果你真的想保留编号索引,我几乎要重组数据:
$items[] = array("A", "Test"); $items[] = array("B", "Test"); $items[] = array("C", "Test"); $items[] = array("D", "Test"); foreach($items as $key => $value) { echo $key.' is a '.$value[0].' containing '.$value[1]; }
答案 1 :(得分:4)
你可以这样做:
$items[A] = "Test";
$items[B] = "Test";
$items[C] = "Test";
$items[D] = "Test";
for($i=0;$i<count($items);$i++)
{
list($key,$value) = each($items[$i]);
echo "$i $key contains $value";
}
我之前没有这样做,但理论上它应该有用。
答案 2 :(得分:1)
小心你在那里如何定义你的钥匙。虽然您的示例有效,但可能并非总是如此:
$myArr = array();
$myArr[A] = "a"; // "A" is assumed.
echo $myArr['A']; // "a" - this is expected.
define ('A', 'aye');
$myArr2 = array();
$myArr2[A] = "a"; // A is a constant
echo $myArr['A']; // error, no key.
print_r($myArr);
// Array
// (
// [aye] => a
// )