iPhone SDK中前景中的本地通知

Question

当应用程序处于前台并且当前正在iPhone SDK中运行时，是否会显示本地通知？

Answer 1

不，您将在appdelegate收到通知。

- (void) application:(UIApplication *)application didReceiveLocalNotification:    (UILocalNotification *)notification {
    //Place your code to handle the notification here.
}

Answer 2

我创建了一个lib来制作与本地通知几乎相同的动画。

检查一下： https://github.com/OpenFibers/OTNotification

演示：

当您在

中收到消息时，可以向此lib发布新消息

- (void) application:(UIApplication *)application didReceiveLocalNotification:    (UILocalNotification *)notification
{
    OTNotificationManager *notificationManager = [OTNotificationManager defaultManager];
    OTNotificationMessage *notificationMessage = [[OTNotificationMessage alloc] init];
    notificationMessage.title = [self notificationTitle];
    notificationMessage.message = @"A notification. Touch me to hide me.";
    [notificationManager postNotificationMessage:notificationMessage];
}

Answer 3

接受的anser是对的，但是接收所有通知并向用户显示内容是不够的

- (void) application:(UIApplication *)application didReceiveLocalNotification:    (UILocalNotification *)notification {

您必须检查，是否是当前通知。 有时会触发另一个通知（例如，当您取消它们时）。所以，你必须检查，这是你除了：

- (void)application:(UIApplication *)application didReceiveLocalNotification:(UILocalNotification *)notification {
    if (fabs([[NSDate date] timeIntervalSinceDate:[notification fireDate]]) <= 0.5f)
    {
        [[[UIAlertView alloc] initWithTitle:NSLocalizedString(@"Notification alert", @"")
                                    message:notification.alertBody
                                   delegate:self
                          cancelButtonTitle:@"Ok" otherButtonTitles:nil] show];    
    }
}

Answer 4

如果您的应用当前处于前台，则会在您的代理中调用以下函数：

- (void)application:(UIApplication *)application didReceiveLocalNotification:(UILocalNotification *)Notifikation

然后您可以决定显示警报视图，但标准视图不会自动显示

Answer 5

Swift 2.2：

func application(application: UIApplication, didReceiveLocalNotification notification: UILocalNotification) {
    var state = application.applicationState
    if state == .Active {
        // handle the notification, e.g. show an alert 
    } 
}

Swift 3.0：

func application(_ application: UIApplication, didReceive notification: UILocalNotification) {
    var state: UIApplicationState = application.applicationState
    if state == .active {
        // handle the notification, e.g. show an alert
    }
}