Question

代码任务：
使用该命令时，机器人会显示所有服务器参与者的列表。

我的问题：
我的问题是我的列表是根据我的未知排序发布的。

我希望它看起来像什么：
我希望参与者按登录服务器的用户进行排序。还有，如果不难，就在昵称旁边加一个对应的数字。

为了更详细的理解，我在下面添加了现在的样子和应该是什么样子的照片。

代码：

from discord.ext import commands
import discord
import asyncio
import math

Bot = commands.Bot(command_prefix=commands.when_mentioned_or("c:"), intents=discord.Intents.all())

@Bot.command()
@commands.is_owner()
async def members(ctx):
    members = [str(m) for m in ctx.guild.members]
    per_page = 10 
    pages = math.ceil(len(members) / per_page)
    cur_page = 1
    chunk = members[:per_page]
    linebreak = "\n"
    memberCount = str(ctx.guild.member_count)
    embed = discord.Embed(title=f"Page {cur_page}/{pages}:\n", description = f"{linebreak.join(chunk)}")
    embed.set_footer(text = f'Members: {memberCount}')
    message = await ctx.send(embed = embed)
    await message.add_reaction("◀️")
    await message.add_reaction("▶️")
    active = True

    def check(reaction, user):
        return user == ctx.author and str(reaction.emoji) in ["◀️", "▶️"]

    while active:
        try:
            reaction, user = await Bot.wait_for("reaction_add", timeout=60, check=check)

            if str(reaction.emoji) == "▶️" and cur_page != pages:
                cur_page += 1
                if cur_page != pages:
                    chunk = members[(cur_page-1)*per_page:cur_page*per_page]
                    memberCount = str(ctx.guild.member_count)
                    embed = discord.Embed(title=f"Page {cur_page}/{pages}:\n", description = f"{linebreak.join(chunk)}")
                    embed.set_footer(text = f'Members: {memberCount}')
                else:
                    chunk = members[(cur_page-1)*per_page:]
                    memberCount = str(ctx.guild.member_count)
                    embed = discord.Embed(title=f"Page {cur_page}/{pages}:\n", description = f"{linebreak.join(chunk)}")
                    embed.set_footer(text = f'Members: {memberCount}')
                await message.edit(embed = embed)
                await message.remove_reaction(reaction, user)

            elif str(reaction.emoji) == "◀️" and cur_page > 1:
                cur_page -= 1
                chunk = members[(cur_page-1)*per_page:cur_page*per_page]
                memberCount = str(ctx.guild.member_count)
                embed = discord.Embed(title=f"Page {cur_page}/{pages}:\n", description = f"{linebreak.join(chunk)}")
                embed.set_footer(text = f'Members: {memberCount}')
                await message.edit(embed=embed) 
                await message.remove_reaction(reaction, user)
        except asyncio.TimeoutError:
            await message.delete()
            active = False

How should I be on the list

How does it show me in the list

How it should look like

Answer 1

这两件事都可以相对容易地完成。

您可以使用sorted函数并根据joined_at属性对成员进行排序

members = [str(m) for m in sorted(ctx.guild.members, key=lambda m: m.joined_at)]

要添加数字，您可以使用 enumerate 函数。

members = [f"{i}. {m}" for i, m in enumerate(members, start=1)]

您可以将所有内容合并为一行

members = [f"{i}. {m}" for i, m in enumerate(sorted(ctx.guild.members, key=lambda m: m.joined_at), start=1)]

不和谐.py |排序成员的

1 个答案: