mongodb找到问题

Question

<_>在user_history集合中

user_name: john
eat : [{food:'apple', timestamp:123}, {food:'cheese', timestamp:80}]

user_name: paul
eat : [{food:'melon', timestamp:125}, {food:'bread', timestamp:60}]

user_name: mattew
eat : [{food:'water', timestamp:90}, {food:'pizza', timestamp:91}]

我需要获得时间戳超过100的食物

我的代码：

db.user_history.find({"eat.timestamp":{$gte:100}},{"eat.food":1})

结果：

{'_id': ObjectId('......'),'eat':[{food:'apple'},{food:'cheeza'}]},
{'_id': ObjectId('......'),'eat':[{food:'melon'},{food:'bread'}]}

我想得到的结果：

{'_id': ObjectId('......'), 'eat':{food:apple}},
{'_id': ObjectId('......'), 'eat':{food:melon}}

我怎么能得到这个？

Answer 1

我认为不可能，请看门票：https://jira.mongodb.org/browse/SERVER-828。 看起来这个问题是already asked