打开XML文件并获取某些内容？

Question

我有以下网址：

http://en.wikipedia.org/wiki/Special:Export/Birkdale,_Queensland

我希望得到以下内容：

pop      = 13,460 (2006 census)
lga      = Redland City
dist1    = 44
near-nw  = [[Thorneside, Queensland|Thorneside]]
| near-n   = 
| near-ne  = [[Wellington Point, Queensland|Wellington Point]]
| near-w   = [[Ransome, Queensland|Ransome]]
| near-e   = [[Wellington Point, Queensland|Wellington Point]]
| near-sw  = [[Capalaba West, Queensland|Capalaba West]]
| near-s   = [[Capalaba, Queensland|Capalaba]]
| near-se  = [[Alexandra Hills, Queensland|Alexandra Hills]]

我想将它们作为变量返回，例如：

$pop = "13,460 (2006 census)";
$lga = "Redland City";
$distance = 44;
$nearnw = "Thorneside";
$nearn = "";
$nearne = "Wellington Point";
$nearw = "Ransome";
$neare = "Wellington Point";
$nearsw = "Capalaba West";
$nears = "Capalaba";
$nearse = "Alexandra Hills";

我如何从这个XML文件中提取信息并将它们放入变量中，如上所述？

谢谢。

Answer 1

您是否尝试过使用simplexml

$url = "http://en.wikipedia.org/wiki/Special:Export/Birkdale,_Queensland";

$xml = simplexml_load_file($url);