Question

我不知道这是否是远程正确的。我有一个类，如果当前存在的字段我想更新数据库，如果不存在则插入。复杂的是我正在加入3个表（set_colors，school_art，baseimage）

任何帮助都会非常棒。

这就是我所拥有的：

public function set_layer_colors($value) {
global $db;

$result_array = mysql_query("
IF EXISTS(SELECT * FROM set_colors WHERE school_art_id = '{$value}')

  UPDATE set_colors (school_art_id, baseimage_id, sub_folder, layer)
    SELECT school_art.id, baseimage.id, baseimage.sub_folder, baseimage.layer
    FROM school_art 
    JOIN baseimage ON baseimage.base_folder = school_art.series_code 
    WHERE baseimage.image_type = 'B' ORDER BY school_art.id 

ELSE

 INSERT INTO set_colors (school_art_id, baseimage_id, sub_folder, layer)
    SELECT school_art.id, baseimage.id, baseimage.sub_folder, baseimage.layer
    FROM school_art 
    JOIN baseimage ON baseimage.base_folder = school_art.series_code 
    WHERE baseimage.image_type = 'B' ORDER BY school_art.id 
    ");

return $result_array;

}

提前致谢。

Answer 1

我相信您正在寻找以下语法

INSERT INTO <table> (field1, field2, field3, ...) 
VALUES ('value1', 'value2','value3', ...)
ON DUPLICATE KEY UPDATE
field1='value1', field2='value2', field3='value3', ...

Answer 2

两种选择：

MySQL Manual :: INSERT INTO ... ON DUPLICATE KEY UPDATE Syntax

或

MySQL Manual :: REPLACE INTO Syntax

两者都允许您在一个查询中执行insert-if-not-exists-or update。

PHP MYSQL更新如果存在或INSERT如果不存在？

2 个答案: