如何将对象序列化为查询字符串格式？我似乎无法在谷歌上找到答案。感谢。
以下是我将序列化的对象作为示例。
public class EditListItemActionModel
{
public int? Id { get; set; }
public int State { get; set; }
public string Prefix { get; set; }
public string Index { get; set; }
public int? ParentID { get; set; }
}
答案 0 :(得分：83)
我99％肯定没有内置的实用工具方法。这不是一项非常常见的任务，因为Web服务器通常不会使用URLEncoded键/值字符串响应。
您如何看待混合反射和LINQ？这有效：
var foo = new EditListItemActionModel() {
Id = 1,
State = 26,
Prefix = "f",
Index = "oo",
ParentID = null
};
var properties = from p in foo.GetType().GetProperties()
where p.GetValue(foo, null) != null
select p.Name + "=" + HttpUtility.UrlEncode(p.GetValue(foo, null).ToString());
// queryString will be set to "Id=1&State=26&Prefix=f&Index=oo"
string queryString = String.Join("&", properties.ToArray());
更新
要编写一个返回任何1-deep对象的QueryString表示的方法，您可以这样做：
public string GetQueryString(object obj) {
var properties = from p in obj.GetType().GetProperties()
where p.GetValue(obj, null) != null
select p.Name + "=" + HttpUtility.UrlEncode(p.GetValue(obj, null).ToString());
return String.Join("&", properties.ToArray());
}
// Usage:
string queryString = GetQueryString(foo);
您还可以将其作为一种扩展方法，而无需额外的工作
public static class ExtensionMethods {
public static string GetQueryString(this object obj) {
var properties = from p in obj.GetType().GetProperties()
where p.GetValue(obj, null) != null
select p.Name + "=" + HttpUtility.UrlEncode(p.GetValue(obj, null).ToString());
return String.Join("&", properties.ToArray());
}
}
// Usage:
string queryString = foo.GetQueryString();
答案 1 :(得分：11)
在其他评论的好主意基础上，我制作了一个通用扩展方法.ToQueryString（），可以在任何对象上使用。
public static class UrlHelpers
{
public static string ToQueryString(this object request, string separator = ",")
{
if (request == null)
throw new ArgumentNullException("request");
// Get all properties on the object
var properties = request.GetType().GetProperties()
.Where(x => x.CanRead)
.Where(x => x.GetValue(request, null) != null)
.ToDictionary(x => x.Name, x => x.GetValue(request, null));
// Get names for all IEnumerable properties (excl. string)
var propertyNames = properties
.Where(x => !(x.Value is string) && x.Value is IEnumerable)
.Select(x => x.Key)
.ToList();
// Concat all IEnumerable properties into a comma separated string
foreach (var key in propertyNames)
{
var valueType = properties[key].GetType();
var valueElemType = valueType.IsGenericType
? valueType.GetGenericArguments()[0]
: valueType.GetElementType();
if (valueElemType.IsPrimitive || valueElemType == typeof (string))
{
var enumerable = properties[key] as IEnumerable;
properties[key] = string.Join(separator, enumerable.Cast<object>());
}
}
// Concat all key/value pairs into a string separated by ampersand
return string.Join("&", properties
.Select(x => string.Concat(
Uri.EscapeDataString(x.Key), "=",
Uri.EscapeDataString(x.Value.ToString()))));
}
}
如果对象具有Array类型和泛型Lists，如果它们只包含基元或字符串，它也适用。
尝试一下，欢迎发表评论：Serialize object into a query string with Reflection
答案 2 :(得分：8)
基于流行的答案，我还需要更新代码以支持数组。分享实施：
public string GetQueryString(object obj)
{
var result = new List<string>();
var props = obj.GetType().GetProperties().Where(p => p.GetValue(obj, null) != null);
foreach (var p in props)
{
var value = p.GetValue(obj, null);
var enumerable = value as ICollection;
if (enumerable != null)
{
result.AddRange(from object v in enumerable select string.Format("{0}={1}", p.Name, HttpUtility.UrlEncode(v.ToString())));
}
else
{
result.Add(string.Format("{0}={1}", p.Name, HttpUtility.UrlEncode(value.ToString())));
}
}
return string.Join("&", result.ToArray());
}
答案 3 :(得分：1)
public static class UrlHelper
{
public static string ToUrl(this Object instance)
{
var urlBuilder = new StringBuilder();
var properties = instance.GetType().GetProperties(BindingFlags.Instance | BindingFlags.Public);
for (int i = 0; i < properties.Length; i++)
{
urlBuilder.AppendFormat("{0}={1}&", properties[i].Name, properties[i].GetValue(instance, null));
}
if (urlBuilder.Length > 1)
{
urlBuilder.Remove(urlBuilder.Length - 1, 1);
}
return urlBuilder.ToString();
}
}
答案 4 :(得分：1)
上述内容的另一种变化，但是我想利用模型类中现有的DataMember属性，因此只有要序列化的属性才通过GET请求发送到url中的服务器。
public string ToQueryString(object obj)
{
if (obj == null) return "";
return "?" + string.Join("&", obj.GetType()
.GetProperties()
.Where(p => Attribute.IsDefined(p, typeof(DataMemberAttribute)) && p.GetValue(obj, null) != null)
.Select(p => $"{p.Name}={Uri.EscapeDataString(p.GetValue(obj).ToString())}"));
}
答案 5 :(得分：1)
这是我的解决方案：
public static class ObjectExtensions
{
public static string ToQueryString(this object obj)
{
if (!obj.GetType().IsComplex())
{
return obj.ToString();
}
var values = obj
.GetType()
.GetProperties()
.Where(o => o.GetValue(obj, null) != null);
var result = new QueryString();
foreach (var value in values)
{
if (!typeof(string).IsAssignableFrom(value.PropertyType)
&& typeof(IEnumerable).IsAssignableFrom(value.PropertyType))
{
var items = value.GetValue(obj) as IList;
if (items.Count > 0)
{
for (int i = 0; i < items.Count; i++)
{
result = result.Add(value.Name, ToQueryString(items[i]));
}
}
}
else if (value.PropertyType.IsComplex())
{
result = result.Add(value.Name, ToQueryString(value));
}
else
{
result = result.Add(value.Name, value.GetValue(obj).ToString());
}
}
return result.Value;
}
private static bool IsComplex(this Type type)
{
var typeInfo = type.GetTypeInfo();
if (typeInfo.IsGenericType && typeInfo.GetGenericTypeDefinition() == typeof(Nullable<>))
{
// nullable type, check if the nested type is simple.
return IsComplex(typeInfo.GetGenericArguments()[0]);
}
return !(typeInfo.IsPrimitive
|| typeInfo.IsEnum
|| type.Equals(typeof(Guid))
|| type.Equals(typeof(string))
|| type.Equals(typeof(decimal)));
}
}
我将此扩展用于集成测试，它可以完美运行：）
答案 6 :(得分：1)
对于嵌套对象也将很有用
string queryString = new
{
myClass = new MyClass
{
FirstName = "john",
LastName = "doe"
},
myArray = new int[] { 1, 2, 3, 4 },
}.ToQueryString();
public static class HttpQueryStrings
{
public static string ToQueryString<T>(this T @this) where T : class
{
StringBuilder query = @this.ToQueryString("");
if (query.Length > 0)
query[0] = '?';
return query.ToString();
}
private static StringBuilder ToQueryString<T>(this T obj, string prefix = "") where T : class
{
StringBuilder gatherer = new StringBuilder();
foreach (var p in obj.GetType().GetProperties(BindingFlags.Public | BindingFlags.Instance))
{
if (p.GetValue(obj, new object[0]) != null)
{
var value = p.GetValue(obj, new object[0]);
if (p.PropertyType.IsArray && value.GetType() == typeof(DateTime[]))
foreach (var item in value as DateTime[])
gatherer.Append($"&{prefix}{p.Name}={item.ToString("yyyy-MM-dd")}");
else if (p.PropertyType.IsArray)
foreach (var item in value as Array)
gatherer.Append($"&{prefix}{p.Name}={item}");
else if (p.PropertyType == typeof(string))
gatherer.Append($"&{prefix}{p.Name}={value}");
else if (p.PropertyType == typeof(DateTime) && !value.Equals(Activator.CreateInstance(p.PropertyType))) // is not default
gatherer.Append($"&{prefix}{p.Name}={((DateTime)value).ToString("yyyy-MM-dd")}");
else if (p.PropertyType.IsValueType && !value.Equals(Activator.CreateInstance(p.PropertyType))) // is not default
gatherer.Append($"&{prefix}{p.Name}={value}");
else if (p.PropertyType.IsClass)
gatherer.Append(value.ToQueryString($"{prefix}{p.Name}."));
}
}
return gatherer;
}
}
答案 7 :(得分：0)
我写的这些内容可以满足您的需求。
public string CreateAsQueryString(PageVariables pv) //Pass in your EditListItemActionModel instead
{
int i = 0;
StringBuilder sb = new StringBuilder();
foreach (var prop in typeof(PageVariables).GetProperties())
{
if (i != 0)
{
sb.Append("&");
}
var x = prop.GetValue(pv, null).ToString();
if (x != null)
{
sb.Append(prop.Name);
sb.Append("=");
sb.Append(x.ToString());
}
i++;
}
Formating encoding = new Formating();
// I am encoding my query string - but you don''t have to
return "?" + HttpUtility.UrlEncode(encoding.RC2Encrypt(sb.ToString()));
}
答案 8 :(得分：0)
面对我所做的类似情况，XML是序列化对象并将其作为查询字符串参数传递。 这种方法的困难在于，尽管编码，接收形式抛出异常说“有潜在危险的请求......”。我的方法是加密序列化对象然后编码以传递它作为查询字符串参数。这反过来使查询字符串防篡改（奖励徘徊到HMAC领域）！
FormA XML序列化对象＆gt;加密序列化字符串＆gt;编码＆gt;作为查询字符串传递给FormB FormB解密查询参数值（也作为request.querystring解码）＆gt;使用XmlSerializer将生成的XML字符串反序列化为对象。
我可以根据请求分享我的VB.NET代码到howIdidit-at-applecart-dot-net
答案 9 :(得分：0)
我正在为Windows 10（UWP）应用寻找解决方案。采用Dave建议的Relection方法，并在添加Microsoft.AspNet.WebApi.Client Nuget包之后，我使用了以下代码， 它处理属性值的Url编码：
private void AddContentAsQueryString(ref Uri uri, object content)
{
if ((uri != null) && (content != null))
{
UriBuilder builder = new UriBuilder(uri);
HttpValueCollection query = uri.ParseQueryString();
IEnumerable<PropertyInfo> propInfos = content.GetType().GetRuntimeProperties();
foreach (var propInfo in propInfos)
{
object value = propInfo.GetValue(content, null);
query.Add(propInfo.Name, String.Format("{0}", value));
}
builder.Query = query.ToString();
uri = builder.Uri;
}
}
答案 10 :(得分：0)
这些方法不适用于此属性之王：
public List<int?> list
答案 11 :(得分：0)
一种支持列表属性的简单方法：
public static class UriBuilderExtensions
{
public static UriBuilder SetQuery<T>(this UriBuilder builder, T parameters)
{
var fragments = typeof(T).GetProperties()
.Where(property => property.CanRead)
.Select(property => new
{
property.Name,
Value = property.GetMethod.Invoke(parameters, null)
})
.Select(pair => new
{
pair.Name,
List = (!(pair.Value is string) && pair.Value is IEnumerable list ? list.Cast<object>() : new[] { pair.Value })
.Select(element => element?.ToString())
.Where(element => !string.IsNullOrEmpty(element))
})
.Where(pair => pair.List.Any())
.SelectMany(pair => pair.List.Select(value => Uri.EscapeDataString(pair.Name) + '=' + Uri.EscapeDataString(value)));
builder.Query = string.Join("&", fragments);
return builder;
}
}
一种更快的解决方案，其速度与拼写每种类型的代码的速度一样快：
public static class UriBuilderExtensions
{
public static UriBuilder SetQuery<TSource>(this UriBuilder builder, TSource parameters)
{
var fragments = Cache<TSource>.Properties
.Select(property => new
{
property.Name,
List = property.FetchValue(parameters)?.Where(item => !string.IsNullOrEmpty(item))
})
.Where(parameter => parameter.List?.Any() ?? false)
.SelectMany(pair => pair.List.Select(item => Uri.EscapeDataString(pair.Name) + '=' + Uri.EscapeDataString(item)));
builder.Query = string.Join("&", fragments);
return builder;
}
/// <summary>
/// Caches dynamically emitted code which converts a types getter property values to a list of strings.
/// </summary>
/// <typeparam name="TSource">The type of the object being serialized</typeparam>
private static class Cache<TSource>
{
public static readonly IEnumerable<IProperty> Properties =
typeof(TSource).GetProperties()
.Where(propertyInfo => propertyInfo.CanRead)
.Select(propertyInfo =>
{
var source = Expression.Parameter(typeof(TSource));
var getter = Expression.Property(source, propertyInfo);
var cast = Expression.Convert(getter, typeof(object));
var expression = Expression.Lambda<Func<TSource, object>>(cast, source).Compile();
return new Property
{
Name = propertyInfo.Name,
FetchValue = typeof(IEnumerable).IsAssignableFrom(propertyInfo.PropertyType) && propertyInfo.PropertyType != typeof(string) ?
CreateListFetcher(expression) :
CreateValueFetcher(expression)
};
})
.OrderBy(propery => propery.Name)
.ToArray();
/// <summary>
/// Creates a function which serializes a <see cref="IEnumerable"/> property value to a list of strings.
/// </summary>
/// <param name="get">A lambda function which retrieves the property value from a given source object.</param>
private static Func<TSource, IEnumerable<string>> CreateListFetcher(Func<TSource, object> get)
=> obj => ((IEnumerable)get(obj))?.Cast<object>().Select(item => item?.ToString());
/// <summary>
/// Creates a function which serializes a <see cref="object"/> property value to a list of strings.
/// </summary>
/// <param name="get">A lambda function which retrieves the property value from a given source object.</param>
private static Func<TSource, IEnumerable<string>> CreateValueFetcher(Func<TSource, object> get)
=> obj => new[] { get(obj)?.ToString() };
public interface IProperty
{
string Name { get; }
Func<TSource, IEnumerable<string>> FetchValue { get; }
}
private class Property : IProperty
{
public string Name { get; set; }
public Func<TSource, IEnumerable<string>> FetchValue { get; set; }
}
}
}
使用任一解决方案的示例：
var url = new UriBuilder("test.com").SetQuerySlow(new
{
Days = new[] { WeekDay.Tuesday, WeekDay.Wednesday },
Time = TimeSpan.FromHours(14.5),
Link = "conferences.com/apple/stream/15",
Pizzas = default(int?)
}).Uri;
输出：
http://test.com/Days=Tuesday&Days=Wednesday&Time=14:30:00&Link=conferences.com%2Fapple%2Fstream%2F15
两种解决方案都不能处理外来类型，索引参数或嵌套参数。
当手动序列化更为简单时，这种c＃7 / .net4.7方法可以帮助您：
public static class QueryParameterExtensions
{
public static UriBuilder SetQuery(this UriBuilder builder, params (string Name, object Obj)[] parameters)
{
var list = parameters
.Select(parameter => new
{
parameter.Name,
Values = SerializeToList(parameter.Obj).Where(value => !string.IsNullOrEmpty(value))
})
.Where(parameter => parameter.Values.Any())
.SelectMany(parameter => parameter.Values.Select(item => Uri.EscapeDataString(parameter.Name) + '=' + Uri.EscapeDataString(item)));
builder.Query = string.Join("&", list);
return builder;
}
private static IEnumerable<string> SerializeToList(object obj)
{
switch (obj)
{
case string text:
yield return text;
break;
case IEnumerable list:
foreach (var item in list)
{
yield return SerializeToValue(item);
}
break;
default:
yield return SerializeToValue(obj);
break;
}
}
private static string SerializeToValue(object obj)
{
switch (obj)
{
case bool flag:
return flag ? "true" : null;
case byte number:
return number == default(byte) ? null : number.ToString();
case short number:
return number == default(short) ? null : number.ToString();
case ushort number:
return number == default(ushort) ? null : number.ToString();
case int number:
return number == default(int) ? null : number.ToString();
case uint number:
return number == default(uint) ? null : number.ToString();
case long number:
return number == default(long) ? null : number.ToString();
case ulong number:
return number == default(ulong) ? null : number.ToString();
case float number:
return number == default(float) ? null : number.ToString();
case double number:
return number == default(double) ? null : number.ToString();
case DateTime date:
return date == default(DateTime) ? null : date.ToString("s");
case TimeSpan span:
return span == default(TimeSpan) ? null : span.ToString();
case Guid guid:
return guid == default(Guid) ? null : guid.ToString();
default:
return obj?.ToString();
}
}
}
用法示例：
var uri = new UriBuilder("test.com")
.SetQuery(("days", standup.Days), ("time", standup.Time), ("link", standup.Link), ("pizzas", standup.Pizzas))
.Uri;
答案 12 :(得分：0)
这种通用方法也许会有用：
public static string ConvertToQueryString<T>(T entity) where T: class
{
var props = typeof(T).GetProperties();
return $"?{string.Join('&', props.Where(r=> r.GetValue(entity) != null).Select(r => $"{HttpUtility.UrlEncode(r.Name)}={HttpUtility.UrlEncode(r.GetValue(entity).ToString())}"))}";
}
答案 13 :(得分：0)
通过序列化然后反序列化为键值对，使用Json.Net会容易得多。
这是一个代码示例：
using Newtonsoft.Json;
using System.Web;
string ObjToQueryString(object obj)
{
var step1 = JsonConvert.SerializeObject(obj);
var step2 = JsonConvert.DeserializeObject<IDictionary<string, string>>(step1);
var step3 = step2.Select(x => HttpUtility.UrlEncode(x.Key) + "=" + HttpUtility.UrlEncode(x.Value));
return string.Join("&", step3);
}