Question

我尝试提取以下单词“good”后面的单词：

lu = ["Don't waste your time with season two.  She could be fun if she wasn't so hateful inside.  Not good.*  Yuck.",
      "I only watched one episode. It had too much nudity and sex in it. The story line was good but didn't enjoy the rest."]

代码是：

import re
lu = ["Don't waste your time with season two.  She could be fun if she wasn't so hateful inside.  Not good.*  Yuck.",
      "I only watched one episode. It had too much nudity and sex in it. The story line was good but didn't enjoy the rest."]
rx = re.compile(r'good\s+(\w+)')
user = tuple(map(lambda x: x.group(1) or "", map(rx.search, f)))
print(user)

但我得到的输出是：

AttributeError: 'NoneType' object has no attribute 'group'

我希望获得的输出是：

('Yuck', 'but')

或：

(['Yuck'], ['but'])

当我从 lu 中删除点 (.) 时，程序运行没有错误，但我不想手动删除点 (.)。谁能帮帮我

Answer 1

问题在于您的正则表达式 is not matching the first string。

要处理这种情况，您需要检查 x 是否为 None：

rx = re.compile(r'good\s+(\w+)')
user = tuple(map(lambda x: "" if x is None else x.group(1), map(rx.search, lu)))

print(user)
# Outputs ('', 'but')

修正正则表达式：

rx = re.compile(r'good[^\w]+(\w+)')
user = tuple(map(lambda x: "" if x is None else x.group(1), map(rx.search, lu)))

print(user)
# Outputs ('Yuck', 'but')

在python中使用```import re```查找关键字后面的单词

1 个答案: