Ansible 如何在所有主机上运行剧本时不考虑主机不属于组（甚至不跳过）

Question

我正在所有主机上运行剧本 sttaus_check。它将从所有主机获取各个进程的状态并打印到控制台。

我有不同的任务，例如针对不同组的 Mongo & Rabbitmq groupA & groupB

[groupA]
127.0.0.1
127.0.0.2
127.0.0.3

[groupB]
127.0.0.2
127.0.0.3

status_check.yaml

- hosts: all
  tasks:
    - name: Check Mongo service status when multi region is false
      shell:  ps -ef| grep [m]ongo 1>/dev/null || [ $? -eq 0 ] && echo "UP" || echo "DOWN"
      register: mongod_status
      no_log: True
      when:
        - "'groupA' in group_names"
    
    - name: Format mongo status
      when:
        - "'groupA' in group_names"
      import_role:
        name: library
        tasks_from: format_process_status
      vars:
        Service: mongod
        group: groupA
        status: "{{ mongod_status.stdout_lines }}"
    
    - name: Check Rabbitmq service status
      shell: ps -ef| grep [b]eam.smp 1>/dev/null || [ $? -eq 0 ] && echo "UP" || echo "DOWN"
      register: rmq_status
      when:
        - "'groupB' in group_names"
    
    - name: Format rabbitmq status
      when:
        - "'clusterB' in group_names"
      import_role:
        name: library
        tasks_from: format_process_status
      vars:
        Service: rabbitmq
        group: groupB
        status: "{{ rmq_status.stdout_lines }}"

TL;DR

format_process_status 扮演库角色：

- name: Print {{ Service }} Stauts from each host of group
  block:
  - name: Converting {{Service}} status into list
    no_log: True
    set_fact:
      status_list: "{{ status| list}}"

  - block:
    - name: Extract hostvars of the hosts from the group and create the list of the host-status dictionaries
      no_log: True
      set_fact:
        status_dict: "{{ groups[group]|map('extract', hostvars)|list|json_query('[].{host: ansible_hostname,status: status_list }') }}"

    - name: Formating status_dict into readable format
      no_log: True
      set_fact:
        service_status: "{{ service_status|default({}) | combine ( {item.host : item.status|join('\n') }) }}"
      with_items: "{{ status_dict }}"

    - name: Converting generic dict var name to {{ Service }}_status specific var
      no_log: True
      set_fact:
        "{{ Service}}_status": "{{ service_status }}"

    - name: Below is the {{Service}} Service status from each host of group
      debug: var={{ Service }}_status
    run_once: true

以上在从 mongo 获取 groupA 状态时工作正常。下面是输出。

ok: [127.0.0.1] => {
    "mongod_status": {
        "127.0.0.1": "UP",
        "127.0.0.2": "UP",
        "127.0.0.3": "UP"
    }
}

但是当从 rabbitmq 获取 groupB 时，它跳过主机 127.0.0.1 因为它不是 groupB 的一部分，因为 run_once 在 {{ 1}} 带有 format_process_status.yml 的所有任务都将被跳过。

Rabbitmq 输出：-

run_once

我怎么能不考虑（甚至不跳过）不属于 TASK [library : debug] skipping: [127.0.0.1] ok: [127.0.0.2] => { "status_list": [ "UP" ] } ok: [127.0.0.3] => { "status_list": [ "UP" ] } TASK [library : Extract host vars of the hosts from the group and create the list of the host-status dictionaries] skipping: [127.0.0.1] TASK [library : Formating status_dict into readable format] ********** skipping: [127.0.0.1] 的主机。或者我怎样才能实现所有主机的输出？有没有更好的办法？

注意：因为我有多个小组和各自的流程，所以期待一个不创建单独剧本的解决方案。