Question

我正在使用以下 DataFrame：

id  slotTime    EDD EDD-10M
0   1000000101068957    2021-05-12  2021-12-26  2021-02-26
1   1000000100849718    2021-03-20  2021-04-05  2020-06-05
2   1000000100849718    2021-03-20  2021-04-05  2020-06-05
3   1000000100849718    2021-03-20  2021-04-05  2020-06-05
4   1000000100849718    2021-03-20  2021-04-05  2020-06-05

我只想保留 slotTime 位于 EDD-10M 和 EDD 之间的行：

df['EDD-10M'] < df['slotTime'] < df['EDD']]

我尝试过使用以下方法：

df.loc[df[df['slotTime'] < df['EDD']] & df[df['EDD-10M'] < df['slotTime']]]

但是它产生以下错误

TypeError: ufunc 'bitwise_and' not supported for the input types, and the inputs could not be safely coerced to any supported types according to the casting rule ''safe''

请指教。

要复制上述 DataFrame，请使用以下代码段：

import pandas as pd
from pandas import Timestamp

df = { 
  'id': {0: 1000000101068957,
  1: 1000000100849718,
  2: 1000000100849718,
  3: 1000000100849718,
  4: 1000000100849718,
  5: 1000000100849718,
  6: 1000000100849718,
  7: 1000000100849718,
  8: 1000000100849718,
  9: 1000000100849718},
  'EDD': {0: Timestamp('2021-12-26 00:00:00'),
  1: Timestamp('2021-04-05 00:00:00'),
  2: Timestamp('2021-04-05 00:00:00'),
  3: Timestamp('2021-04-05 00:00:00'),
  4: Timestamp('2021-04-05 00:00:00'),
  5: Timestamp('2021-04-05 00:00:00'),
  6: Timestamp('2021-04-05 00:00:00'),
  7: Timestamp('2021-04-05 00:00:00'),
  8: Timestamp('2021-04-05 00:00:00'),
  9: Timestamp('2021-04-05 00:00:00')},
 'EDD-10M': {0: Timestamp('2021-02-26 00:00:00'),
  1: Timestamp('2020-06-05 00:00:00'),
  2: Timestamp('2020-06-05 00:00:00'),
  3: Timestamp('2020-06-05 00:00:00'),
  4: Timestamp('2020-06-05 00:00:00'),
  5: Timestamp('2020-06-05 00:00:00'),
  6: Timestamp('2020-06-05 00:00:00'),
  7: Timestamp('2020-06-05 00:00:00'),
  8: Timestamp('2020-06-05 00:00:00'),
  9: Timestamp('2020-06-05 00:00:00')},
 'slotTime': {0: Timestamp('2021-05-12 00:00:00'),
  1: Timestamp('2021-03-20 00:00:00'),
  2: Timestamp('2021-03-20 00:00:00'),
  3: Timestamp('2021-03-20 00:00:00'),
  4: Timestamp('2021-03-20 00:00:00'),
  5: Timestamp('2021-03-20 00:00:00'),
  6: Timestamp('2021-03-20 00:00:00'),
  7: Timestamp('2021-03-20 00:00:00'),
  8: Timestamp('2021-03-20 00:00:00'),
  9: Timestamp('2021-03-20 00:00:00')}}

df = pd.DataFrame(df)

Answer 1

你只需要把你的两边分组

df[(df['slotTime'] < df['EDD']) & (df['EDD-10M'] < df['slotTime'])]

否则操作顺序会先尝试 & 事情，然后一切都会崩溃

或者，您可能希望使用 .between 运算符（假设您有一个日期时间序列

df[df['slotTime'].between(df['EDD'],df['EDD-10M'])]

Answer 2

你可以使用已经有人回答过你的 between() 方法或者像这样尝试

df.loc[(df['EDD-10M'] < df['slotTime']) & (df['slotTime'] < df['EDD'])]

你应该使用（和）多个条件

Answer 3

您可以使用 query：

df.query("(slotTime < EDD) & (`EDD-10M` < slotTime)")

基于多个日期条件过滤数据框

3 个答案: