Question

我想在管理员输入激活（用户）时向用户添加角色，机器人为用户提供 3 个角色，这是我的代码

  if (message.content === 'activate') {

  const guild = message.guild;

  const role = message.guild.roles.cache.get('842121303616126977');

  const member =   message.mentions.members.first

  member.roles.add(role);
          
  }
});

Answer 1

GuildMemberRoleManager.add 接受一个 RoleResolvable 数组，它可以是 Role 的一个实例，也可以是一个 Snowflake。

if (message.content === "activate") {
    const member = message.mentions.members.first(); // Note that first is a method, not a property.
    if (!member) return message.channel.send("Member not found.");

    member.roles.add(["RoleID1", "RoleID2", "RoleID3"]);
}

Answer 2

这行得通

this code worked for me finally `client.on('message', message => {
    
    if (!message.content.startsWith(prefix) || message.author.bot) return;

    const args = message.content.slice(prefix.length).split(/ +/);
    console.log(args);

    const command = args.shift().toLowerCase();


    if (command == 'activate') {
    const member = message.mentions.members.first(); // Note that first is a method, not a property.


if (!member) return message.channel.send("member not found");

const drole = message.guild.roles.cache.get('842121300532920362');

const prole = message.guild.roles.cache.get('842121301777973298');

const lrole = message.guild.roles.cache.get('842121302708977694');

const frole = message.guild.roles.cache.get('842121305854836826');

member.roles.add(drole);
member.roles.add(lrole);
member.roles.add(prole);
member.roles.remove(frole);
message.channel.send('activated'  + ' <' + '@' + member + '>');
  }


  });`

discord.js 用 1 个命令添加 3 个角色

2 个答案: