我正在学习 PHP,现在被困住了。在 while 循环中,显示所有待办事项。这些元素中的每一个都有一个删除按钮和一个检查按钮。删除按钮适用于每个元素,但复选按钮仅适用于第一个元素。检查按钮用于检查元素。按下复选按钮时,会显示一条错误消息,指出无法删除此元素。仅在第一个元素中当然不是。我找不到错误。
我怀疑索引有问题
<?php
$todos = $conn->query("SELECT * FROM todos ORDER BY id DESC");
?>
<div class="show-todo-section">
<?php if($todos->rowCount() <= 0){ ?>
<div class="todo-item">
<div class="empty">
<img src="img/f.png" width="100%" />
<img src="img/Ellipsis.gif" width="80px">
</div>
</div>
<?php } ?>
<?php while($todo = $todos->fetch(PDO::FETCH_ASSOC)) { ?>
<div class="todo-item">
<form action="app/checked.php" method="POST">
<button class="check-box" value="<?php echo $todo['id']; ?>" name='checked' type="submit">Check</button>
</form>
<form action="app/delete.php" method="POST">
<button class="remove-to-do" value="<?php echo $todo['id']; ?>" name='delete' type="submit">x</button>
</from>
<?php if($todo['checked']){ ?>
<h2 class="checked"><?php echo $todo['title'] ?></h2>
<?php }else { ?>
<h2><?php echo $todo['title'] ?></h2>
<?php } ?>
<small>created: <?php echo $todo['date_time'] ?></small>
<?php for ($i = 1; $i <= $todo['coins']; $i++) {
echo "<img class='coins' src='img/coin.gif' width='40px' />";
} ?>
</div>
<?php } ?>
</div>
checked.php
<?php
if (isset($_POST['checked'])) {
require '../db_conn.php';
$id = $_POST['checked'];
if(empty($id)){
header("Location: ../index.php?mess=errorChecked". $id);
}else{
$todos = $conn->prepare("SELECT id, checked FROM todos WHERE id=?");
$todos->execute([$id]);
$todo = $todos->fetch();
$uId = $todo['id'];
$checked = $todo['checked'];
$uChecked = $checked ? 0 : 1;
$res = $conn->query("UPDATE todos SET checked=$uChecked WHERE id=$uId");
header("Location: ../index.php?mess=successChecked");
$conn = null;
exit();
}
} else{
header("Location: ../index.php?mess=errorChecked");
}