Question

我需要同步运行异步函数，我尝试了以下方法。但是结果还是异步的，

const asyncFunction = async () => {
  const count = await testSchema.countDocuments(); //Get total count from mongoDB
  console.log("COUNT ", count);
  return count;
};

console.log("BEFORE ASYNC FUNCTION");
(async () => {
  await asyncFunction();
})();
console.log("AFTER ASYNC FUNCTION");

输出，

BEFORE ASYNC FUNCTION
AFTER ASYNC FUNCTION
COUNT  0

Answer 1

您需要将一切包裹在 async 中。如果你说...

async function main() {

  console.log("BEFORE ASYNC FUNCTION");

  await asyncFunction();

  console.log("AFTER ASYNC FUNCTION"); 

}
main();

const asyncFunction = async () => {
  const count = await testSchema.countDocuments(); //Get total count from mongoDB
  console.log("COUNT ", count);
  return count;
};

main() 返回一个 promise 并且是异步的......但我们不在乎。

在同步内运行异步函数

1 个答案: