Question

我是XStream的新手

我关注DTO

@XStreamAlias("outline")
public class OutlineItem implements java.io.Serializable {

    private static final long serialVersionUID = -2321669186524783800L;

    @XStreamAlias("text")
    @XStreamAsAttribute
    private String text;

    @XStreamAlias("removeMe")
    private List<OutlineItem> childItems;
}

一旦我做了

XStream stream = new XStream();
stream.processAnnotations(OutlineItem.class);
stream.toXML(outlineItem);

我将此作为输出文本

<outline text="Test">
  <removeMe>
    <outline text="Test Section1">
      <removeMe>
        <outline text="Sub Section1 1">
          <removeMe/>
        </outline>
        <outline text="Sub Section1 2">
          <removeMe/>
        </outline>
      </removeMe>
    </outline>
    <outline text="Test Section 2">
      <removeMe>
        <outline text="Test Section2 1">
          <removeMe/>
        </outline>
      </removeMe>
    </outline>
  </removeMe>
</outline>

而我希望输出为：

<outline text="Test">
    <outline text="Test Section1">
        <outline text="Sub Section1 1">
        </outline>
        <outline text="Sub Section1 2">
        </outline>
    </outline>
    <outline text="Test Section 2">
        <outline text="Test Section2 1">
        </outline>
    </outline>
</outline>

任何帮助将不胜感激！不确定是否需要某种XSLT ......

沙

Answer 1

注意：我是EclipseLink JAXB (MOXy)负责人，也是JAXB（JSR-222）专家组的成员。

我相信答案是：

@XStreamImplicit(itemFieldName="outline")
private List<OutlineItem> childItems;

您是否考虑过使用JAXB实施（Metro，MOXy，JaxMe，...）？

<强> OutlineItem

import javax.xml.bind.annotation.*;

@XmlRootElement(name="outline")
@XmlAccessorType(XmlAccessType.FIELD)
public class OutlineItem implements java.io.Serializable {

    private static final long serialVersionUID = -2321669186524783800L;

    @XmlAttribute
    private String text;

    @XmlElement("outline")
    private List<OutlineItem> childItems;

}

<强>演示

import javax.xml.bind.*;

public class Demo {

    public static void main(String[] args) throws JAXBException {

        JAXBContext jaxbContext = JAXBContext.newInstance(OutlineItem.class);

        Marshaller marshaller = jaxbContext.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.marshal(outlineItem, System.out);

    }

}

XML中的不需要的元素通过XSTREAM

1 个答案: