Question

此方法将调用无状态小部件内的 init 函数。但是如何模拟调用 dispose 函数呢？

    var widget = StatelessWidgetExample();
    await tester.pumpWidget(widget);

我也尝试模拟从树中移除。

    await tester.pumpWidget(widget);
    await tester.pumpWidget(Container());

但是没有用

Answer 1

是这样的


    var key2 = Key('a');
    var testStateful = _TestStateful(
      key: key2,
      child: TestInitDispose(),
    );

    await tester.pumpWidget(testStateful);
    /// will call init

    var state = tester.firstState<__TestStatefulState>(find.byKey(key2));
    state.remove();

    await tester.pump();
    /// will call dispose
  });

...

class _TestStateful extends StatefulWidget {
  final Widget child;
  const _TestStateful({Key? key, required this.child}) : super(key: key);

  @override
  __TestStatefulState createState() => __TestStatefulState();
}

class __TestStatefulState extends State<_TestStateful> {
  bool showChild = true;
  void remove() {
    setState(() {
      showChild = false;
    });
  }

  @override
  Widget build(BuildContext context) {
    return showChild ? widget.child : Container();
  }
}

如何在颤振测试中模拟处理小部件？

1 个答案: