我是ggplot2的新手,想要动态地在现有的情节中绘制线条,但这不起作用。在绘制整个图片时,它只需要最后一次计数。
我有2个矩阵: “clVrd”与
[,1] [,2]
[1,] 0.6618725 -0.04065907
[2,] 0.4646620 0.09859806
[3,] 0.9388307 0.05681554
[4,] 1.1809942 0.12906415
[5,] 1.5476428 0.49644973
[6,] -0.1855485 0.30445869
[7,] 0.4525888 0.49559198
[8,] -0.4004534 -0.06419374
[9,] -1.0669191 0.17292748
[10,] -0.9372038 0.02601539
[11,] 0.5617849 -5.21857716
[12,] -0.9370099 -0.05539107
[13,] 0.6803453 0.21223368
[14,] 1.3040601 0.47598799
和“mid”与
[,1] [,2]
[1,] -0.1958772 0.3012428
[2,] 0.5115807 0.4142237
[3,] -0.6585965 0.2623573
[4,] 0.4680863 -1.4964873
[5,] -1.2431780 0.2383014
[6,] -2.3507773 0.0954886
[7,] -0.5547284 -2.1393520
[8,] 0.1314092 0.3408999
[9,] 0.7592055 -0.8161825
[10,] 0.8247861 0.5152814
[11,] -1.8667328 0.1344475
[12,] -0.4825223 -4.0975561
和一个矩阵“active”告诉循环是否绘制一条线(1)或不是(0)
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11] [,12] [,13]
[1,] 1 1 1 1 1 1 1 1 1 1 0 1 1
[2,] 1 1 1 1 1 1 1 1 1 1 0 1 1
[3,] 1 1 1 1 1 1 1 1 1 1 0 1 1
[4,] 1 1 1 1 1 1 1 1 1 1 1 1 1
[5,] 1 1 1 1 0 1 1 1 1 1 0 1 1
[6,] 0 0 0 0 0 0 0 0 1 1 0 1 0
[7,] 1 1 1 1 1 1 1 1 1 1 1 1 1
[8,] 1 1 1 1 1 1 1 1 1 1 0 1 1
[9,] 1 1 1 1 1 1 1 1 1 1 1 1 1
[10,] 1 1 1 1 1 1 1 1 1 1 0 1 1
[11,] 0 0 0 0 0 1 0 1 1 1 0 1 0
[12,] 1 1 1 1 1 1 1 1 1 1 1 1 1
此调用产生主图
g <- ggplot() + layer(data=data.frame(clUrd), mapping=aes(x=clUrd[,1], y=clUrd[,2]), geom = "point", stat="identity", size = I(1), alpha = I(0.2))
运作良好。现在我想从每个条目y(行)到相应矩阵clVrd中的每个x(col)绘制一条线,如果在active中,则为mid。
我尝试了以下循环:
for (i in 1:13){ # Draw the lines between middlepoints and infrastructures
for (j in 1:maxcl){
if (active[j,i]==1){
g <- g + geom_segment(aes(x=clVrd[i,1], y=clVrd[i,2], xend=mid[j,1], yend=mid[j,2]), color='grey')
}
}
}
哪个不起作用。它只画出i = 13和j = 12的线条。如果我用头(g)调查g,我可以看到他添加了标签
$layers[[132]]
mapping: x = clVrd[i, 1], y = clVrd[i, 2], xend = mid[j, 1], yend = mid[j, 2]
geom_segment: colour = grey
stat_identity:
position_identity: (width = NULL, height = NULL)
这解释了为什么他只绘制i = 13和j = 12的线条。但我怎么能解决这个问题呢?不应该有157层?这里只有132或者我理解错了吗?
感谢您的帮助。
多米尼克
答案 0 :(得分:1)
吃完晚饭后休息一下,我找到了答案。我不知道这是否是最佳解决方案,但它对我有用。
我们生成矩阵“lines”
lines <- numeric()
如果活动[x,y]为1(参见上文),则将来自不同矩阵的行的坐标放在新的矩阵中。
for (i in 1:13){
for (j in 1:maxcl){
if (active[j,i]==1){
lines <- rbind(lines, c(clVrd[i,1], clVrd[i,2], mid[j,1], mid[j,2]))
}
}
}
现在我们可以用
的线条绘制情节g <- ggplot() + layer(data=data.frame(clUrd), mapping=aes(x=clUrd[,1], y=clUrd[,2], col=factor(clUrd[,3])), geom = "point", stat="identity", size = I(1), alpha = I(0.2))
但我仍然要检查一切是否正确,因为它似乎有点,但它应该
现在通过以下调用生成整个图片:
g <- ggplot() + layer(data=data.frame(clUrd), mapping=aes(x=clUrd[,1], y=clUrd[,2], col=factor(clUrd[,3])), geom = "point", stat="identity", size = I(1.5), alpha = I(0.2)) +
scale_colour_brewer(palette="Paired") +
geom_segment(data=data.frame(test), aes(x=lines[,1], y=lines[,2], xend=lines[,3], yend=lines[,4]), color='grey', alpha = I(0.2)) +
layer(data=data.frame(clVrd), mapping=aes(x=clVrd[,1], y=clVrd[,2]), geom = "point", stat="identity", size = I(4), color='black', shape=2) +
layer(data=data.frame(mid), mapping=aes(x=mid[,1], y=mid[,2]), geom = "point", stat="identity", size = I(4), color='black', shape=22) +
opts(legend.position = "none") +
scale_x_continuous('Dimension 1') +
scale_y_continuous('Dimension 2') +
opts(axis.title.y = theme_text(vjust=0.2, angle=90)) +
opts(axis.title.x = theme_text(vjust=0.2, angle=0))
与clUrd是一个3x5982矩阵,如
[1,] -0.1454078 0.26175441 1
[2,] 0.4567384 0.46036161 2
[3,] -0.9269251 0.39196787 3
[4,] -0.8959093 0.06884224 3
[5,] 0.1618442 -1.12006536 4
[6,] -1.4021955 0.34594349 5
结果如下图!点是受访者,三角形是基础设施,正方形是群集的中点,颜色是不同的群集。