我正在使用python绑定实现一个带有zeroMQ的管道模式。
任务被扇出到工作人员,他们用这样的无限循环来监听新任务:
while True:
socks = dict(self.poller.poll())
if self.receiver in socks and socks[self.receiver] == zmq.POLLIN:
msg = self.receiver.recv_unicode(encoding='utf-8')
self.process(msg)
if self.hear in socks and socks[self.hear] == zmq.POLLIN:
msg = self.hear.recv()
print self.pid,":", msg
sys.exit(0)
当他们从汇聚节点收到消息时,他们退出,确认已收到预期的所有结果。
但是,工作人员可能会错过这样的消息而不能完成。什么是让工人总是完成的最好方法,当他们无法知道时(除了通过已经提到的消息,没有其他任务需要处理)。这是我为检查工人状态而编写的测试代码:
#-*- coding:utf-8 -*-
"""
Test module containing tests for all modules of pypln
"""
import unittest
from servers.ventilator import Ventilator
from subprocess import Popen, PIPE
import time
class testWorkerModules(unittest.TestCase):
def setUp(self):
self.nw = 4
#spawn 4 workers
self.ws = [Popen(['python', 'workers/dummy_worker.py'], stdout=None) for i in range(self.nw)]
#spawn a sink
self.sink = Popen(['python', 'sinks/dummy_sink.py'], stdout=None)
#start a ventilator
self.V = Ventilator()
# wait for workers and sinks to connect
time.sleep(1)
def test_send_unicode(self):
'''
Pushing unicode strings through workers to sinks.
'''
self.V.push_load([u'são joão' for i in xrange(80)])
time.sleep(1)
#[p.wait() for p in self.ws]#wait for the workers to terminate
wsr = [p.poll() for p in self.ws]
while None in wsr:
print wsr, [p.pid for p in self.ws if p.poll() == None] #these are the unfinished workers
time.sleep(0.5)
wsr = [p.poll() for p in self.ws]
self.sink.wait()
self.sink = self.sink.returncode
self.assertEqual([0]*self.nw, wsr)
self.assertEqual(0, self.sink)
if __name__ == '__main__':
unittest.main()
答案 0 :(得分:1)
所有消息传递的东西最终都会以心跳结束。如果您(作为工人或水槽或其他任何东西)发现您需要使用的组件已经死亡,您基本上可以尝试连接其他地方或自杀。因此,如果你作为工人发现水槽不再存在,那就退出吧。这也意味着即使接收器仍然存在但是连接断开,您也可以退出。但我不确定你能做得更多,也许更合理地设定所有超时......