Question

我正在尝试在颤动中使用 firebase 实现电话身份验证。但是，在设置用户名时遇到问题。由于用户名为空，应用无法运行。

当我使用电话号码注册时，我在 firebase 控制台的身份验证菜单中看到用户，但是，firestore 不会为用户创建记录。

这里是流程：

Phone icon button press 显示电话输入的警报对话框，otp 被发送到电话号码，输入 otp 后，显示用户名的警报对话框。一旦用户输入用户名并按下确定按钮，我就会收到错误消息：

#create the dataframe
df = pd.DataFrame(None, columns= ['Event', 'Measure', 'Measure2'])
df.loc[len(df)] = ['A', 10, 5]
df.loc[len(df)] = ['B', 11, 7]
df.loc[len(df)] = ['C', 15, 8]
df.loc[len(df)] = ['D', 21, 6]
df.loc[len(df)] = ['E', 3, 4]
print(df)

#get the new dataframe
newdf = df 
newdf[['Measure', 'Measure2']] -= newdf[newdf['Event'] == 'C'][['Measure', 'Measure2']].to_numpy()[0]
newdf

这是警报对话框代码：

Exception caught by gesture ============================================
The following NoSuchMethodError was thrown while handling a gesture:
The method 'registerUser' was called on null.
Receiver: null
Tried calling: registerUser(Instance of 'StatelessElement', "handuh")

register_view_model 类 registerUser 方法：

 showAlertDialog(BuildContext context) async {
  RegisterViewModel viewModel;
  TextEditingController textFieldController = TextEditingController();;
  return showDialog(
      context: context,
      builder: (context) {
        return AlertDialog(
          title: Text(Languages.of(context).mustUsername),
          content: TextField(
              controller: textFieldController,
              textInputAction: TextInputAction.go,
              keyboardType: TextInputType.name,
              decoration: InputDecoration(hintText: Languages.of(context).username),
              onChanged: (String val) {
                setState(() {
                  viewModel.setName(val);
                });}
          ),
          shape: RoundedRectangleBorder( borderRadius: BorderRadius.all(Radius.circular(40.0))),
          actions: <Widget>[
            new TextButton(
                child: new Text(Languages.of(context).done),
                onPressed: () {
                  viewModel.registerUser(context, textFieldController.text);
                  Navigator.pushAndRemoveUntil(context,
              MaterialPageRoute(builder: (context) => TabScreen()),
              (route) => false);
                }
            )
          ],
        );
      }
  );
}

setName 方法：

registerUser(BuildContext context, String username) async {
if ((username != null) && (phone.isNotEmpty)) {
  loading = true;
  notifyListeners();
  try {
    bool success = await auth.createUser(
      name: username,
     phone: phone,
    );
    print(success);
    if (success) {
      Navigator.of(context).pushReplacement(
          CupertinoPageRoute(builder: (_) => ProfilePicture()));
    }
  } catch (e) {
    loading = false;
    notifyListeners();
    print(e);
    showInSnackBar(context, 
'${auth.handleFirebaseAuthError(e.toString())}');
  }
  loading = false;
  notifyListeners();
} else {
  showInSnackBar(context, Languages.of(context).errorOcc);
}
}

非常感谢帮助！

用户注册 firebase 的颤振问题

0 个答案: