我想使用 Python 用正则表达式检测公司名称。
这是我的想法:
我尝试过类似的方法,但它不起作用:
address_1 = 'I work in Amazon.com Inc.'
address_2 = 'Company named Swiss Medic Holding invested in vaccine'
address_3 = 'what do you think about Abercrombie & Fitch Co. ?'
address_4 = 'do you work in Delta Group?'
address_5 = 'I have worked in CocaCola Gmbh'
regex_company = '([A-Z][\w]+[ -]+){1,3}(Ltd|ltd|LTD|llc|LLC|Inc|inc|INC|plc|Corp|Group)'
found = re.search(regex_company, address)
我想打印检测到的公司的结果 我使用相同的正则表达式逻辑来查找街道地址并且效果很好,但对于公司名称则不然。 这是我使用过的正则表达式:
regex_street = "(\d{0,6})(?:\w)\s([A-Z][\w]+[ -]+){1,3}(Street|St|Road|Rd)
正则表达式逻辑:数字+1-3个单词+street/st/road/rd
答案 0 :(得分:2)
使用
\b[A-Z]\w+(?:\.com?)?(?:[ -]+(?:&[ -]+)?[A-Z]\w+(?:\.com?)?){0,2}[,\s]+(?i:ltd|llc|inc|plc|co(?:rp)?|group|holding|gmbh)\b
说明
--------------------------------------------------------------------------------
\b the boundary between a word char (\w) and
something that is not a word char
--------------------------------------------------------------------------------
[A-Z] any character of: 'A' to 'Z'
--------------------------------------------------------------------------------
\w+ word characters (a-z, A-Z, 0-9, _) (1 or
more times (matching the most amount
possible))
--------------------------------------------------------------------------------
(?: group, but do not capture (optional
(matching the most amount possible)):
--------------------------------------------------------------------------------
\. '.'
--------------------------------------------------------------------------------
co 'co'
--------------------------------------------------------------------------------
m? 'm' (optional (matching the most amount
possible))
--------------------------------------------------------------------------------
)? end of grouping
--------------------------------------------------------------------------------
(?: group, but do not capture (between 0 and 2
times (matching the most amount
possible)):
--------------------------------------------------------------------------------
[ -]+ any character of: ' ', '-' (1 or more
times (matching the most amount
possible))
--------------------------------------------------------------------------------
(?: group, but do not capture (optional
(matching the most amount possible)):
--------------------------------------------------------------------------------
& '&'
--------------------------------------------------------------------------------
[ -]+ any character of: ' ', '-' (1 or more
times (matching the most amount
possible))
--------------------------------------------------------------------------------
)? end of grouping
--------------------------------------------------------------------------------
[A-Z] any character of: 'A' to 'Z'
--------------------------------------------------------------------------------
\w+ word characters (a-z, A-Z, 0-9, _) (1 or
more times (matching the most amount
possible))
--------------------------------------------------------------------------------
(?: group, but do not capture (optional
(matching the most amount possible)):
--------------------------------------------------------------------------------
\. '.'
--------------------------------------------------------------------------------
co 'co'
--------------------------------------------------------------------------------
m? 'm' (optional (matching the most
amount possible))
--------------------------------------------------------------------------------
)? end of grouping
--------------------------------------------------------------------------------
){0,2} end of grouping
--------------------------------------------------------------------------------
[,\s]+ any character of: ',', whitespace (\n, \r,
\t, \f, and " ") (1 or more times
(matching the most amount possible))
--------------------------------------------------------------------------------
(?i: group, but do not capture (case-
insensitive) (with ^ and $ matching
normally) (with . not matching \n)
(matching whitespace and # normally):
--------------------------------------------------------------------------------
ltd 'ltd'
--------------------------------------------------------------------------------
| OR
--------------------------------------------------------------------------------
llc 'llc'
--------------------------------------------------------------------------------
| OR
--------------------------------------------------------------------------------
inc 'inc'
--------------------------------------------------------------------------------
| OR
--------------------------------------------------------------------------------
plc 'plc'
--------------------------------------------------------------------------------
| OR
--------------------------------------------------------------------------------
co 'co'
--------------------------------------------------------------------------------
(?: group, but do not capture (optional
(matching the most amount possible)):
--------------------------------------------------------------------------------
rp 'rp'
--------------------------------------------------------------------------------
)? end of grouping
--------------------------------------------------------------------------------
| OR
--------------------------------------------------------------------------------
group 'group'
--------------------------------------------------------------------------------
| OR
--------------------------------------------------------------------------------
holding 'holding'
--------------------------------------------------------------------------------
| OR
--------------------------------------------------------------------------------
gmbh 'gmbh'
--------------------------------------------------------------------------------
) end of grouping
--------------------------------------------------------------------------------
\b the boundary between a word char (\w) and
something that is not a word char
import re
regex = r"\b[A-Z]\w+(?:\.com?)?(?:[ -]+(?:&[ -]+)?[A-Z]\w+(?:\.com?)?){0,2}[,\s]+(?i:ltd|llc|inc|plc|co(?:rp)?|group|holding|gmbh)\b"
test_str = ("I work in Amazon.com Inc.\n"
"Company named Swiss Medic Holding invested in vaccine\n"
"what do you think about Abercrombie & Fitch Co. ?\n"
"do you work in Delta Group?\n"
"I have worked in CocaCola Gmbh")
print(re.findall(regex, test_str))
结果:['Amazon.com Inc', 'Swiss Medic Holding', 'Abercrombie & Fitch Co', 'Delta Group', 'CocaCola Gmbh']
答案 1 :(得分:0)
使用 https://regex101.com 测试正则表达式,很棒。对于您的具体示例,这里是可以满足您要求的正则表达式。在此示例中,我认为不需要测试可选的 .com。
regex_company = '[A-Z]([^ ]*[ &]*){0,2}(Inc\.|Ltd|GmbH|AG|Gmbh|Group|Holding|Co\.)'
for address in [address_1, address_2, address_3, address_4, address_5]:
found = re.search(regex_company, address)
if found:
print(found)
# prints:
# <regex.Match object; span=(10, 25), match='Amazon.com Inc.'>
# <regex.Match object; span=(14, 33), match='Swiss Medic Holding'>
# <regex.Match object; span=(24, 47), match='Abercrombie & Fitch Co.'>
# <regex.Match object; span=(15, 26), match='Delta Group'>
# <regex.Match object; span=(17, 30), match='CocaCola Gmbh'>