我特别想要拉出其中一个表示图像文件夹的节点。我指的节点是channelimagepath。提前谢谢。
这是XML文件:
<channel title="My Title">
<shortname>aa_aaperil</shortname>
<artist>Aesthetic Apparatus</artist>
<channellogosmall>images/asp.jpg</channellogosmall>
<channelimagepath>images/base/flash/aa_aaperil/</channelimagepath>
<channeldesign>images/channel/aa_aaperil/aa_aaperil-design.gif</channeldesign>
<totalimagesback>100</totalimagesback>
<totalimagesmiddle>100</totalimagesmiddle>
<totalimagesfront>100</totalimagesfront>
<pagepath>/artistchannel.php/channel/aa_aaperil</pagepath>
<description><![CDATA[Here's the description.]]></description>
<allowblocking>true</allowblocking>
</channel>
答案 0 :(得分:1)
folder=yourXMLHTTPObject.responseXML.documentElement.getElementsByTagName("channelimagepath");
theFolderYouWant=folder[0].firstChild.nodeValue;
你还需要ajax部分吗?
答案 1 :(得分:0)
的一些变体
var blah = '';
$(xml).find("channelimagepath").each(function(){
blah = $(this).text();
});