Question

import random
random_Number = random.randrange(1, 4)

support = input('Write help to support ')

if support == "help":
    print("this is Rock, Paper, Scissors game ")
    play_Game = input('-enter 1 to Rock\n-enter 2 Paper\n-enter 3 to Scissors \n')
    if random_Number == 1 and play_Game == 1 :
        print('The game is draw\n Try Again!')

    elif random_Number == 2 and play_Game == 1:
        print('You lose!\n Hard luck')

    elif random_Number == 3 and play_Game == 1:
        print('You won!\n Good luck')

    elif random_Number == 1 and play_Game == 2:
        print('You won!\n Good luck')

    elif random_Number == 2 and play_Game == 2:
        print('The game is draw\n Try Again!')

    elif random_Number == 2 and play_Game == 2:
        print('The game is draw\n Try Again!')

    elif random_Number == 3 and play_Game == 2:
        print('You lose!\n Hard luck')

    elif random_Number == 1 and play_Game == 3:
        print('You lose!\n Hard luck')

    elif random_Number == 2 and play_Game == 3:
        print('You won!\n Good luck')

    elif  random_Number == 3 and play_Game == 3:
        print('The game is draw\n Try Again!')
    else:
        print('please, enter a correct number ')


else:
   print("write the true keyword")

评论：当我输入 1、2 或 3 时，它告诉我输入正确的数字，我认为错误在 if 语句中。我学过python，这是我的第一个项目。请告诉我这是一个干净的代码吗？

Answer 1

这是因为您将字符串与整数进行比较。在 python input() 中返回一个字符串。当然，字符串永远不等于整数。

因此。使用 int()

将输入转换为整数

play_Game=int(input('-enter 1 to Rock\n-enter 2 Paper\n-enter 3 to Scissors \n'))

Answer 2

在测试中保留字符串类型并用字符串替换数字可能更安全。这样，如果在提示中输入除数字以外的其他内容，程序就不会崩溃。

play_Game = input('-enter 1 to Rock\n-enter 2 Paper\n-enter 3 to Scissors \n')
if random_Number == "1" and play_Game == "1" :
    print('The game is draw\n Try Again!')

否则，任何非数字输入都会在转换为 int 期间触发错误。

程序有什么问题

2 个答案: