如何拆分数组的字符串元素并将它们添加到另一个？

Question

使用名称数组列表，我尝试使用 for 循环拆分名字和姓氏。该代码有效，但是当使用子字符串拆分名称时，它从 0-x（x 是名称之间的空格）开始，但它每次从 0 读取并多次添加每个名称直到完成。如何每次从下一个元素运行它以跳过先前拆分和添加的名称？

public static void main(String[] args) {

    String [] name_list = {"lee momo", "michael jesus", "kim danger", "dean habbo"};

    ArrayList<String> firstNames = new ArrayList<String>();
    ArrayList<String> surnames = new ArrayList<String>();

    for(int i = 0; i < name_list.length; i++){
        int x = name_list[i].indexOf(" ");
        String firstName = name_list[i].substring(0, x);
        firstNames.add(firstName);

        for(int j = 0; j < name_list.length; j++){
            int y = name_list[i].indexOf(" ");
            String surname = name_list[i].substring(x);
            surnames.add(surname);
        }
        
        System.out.println(firstNames.toString());
        System.out.println(surnames.toString());

    }
}

例如名字的输出是这样的： 李 李，迈克尔 李、迈克尔、金 李、迈克尔、金、院长

Answer 1

修复

您只需要一个循环，即可提取两者

String[] name_list = {"lee momo", "michael jesus", "kim danger", "dean habbo"};
ArrayList<String> firstNames = new ArrayList<>();
ArrayList<String> surnames = new ArrayList<>();
for (int i = 0; i < name_list.length; i++) {
    int x = name_list[i].indexOf(" ");
    String firstName = name_list[i].substring(0, x);
    firstNames.add(firstName);
    String surname = name_list[i].substring(x + 1);
    surnames.add(surname);
}
System.out.println(firstNames); // [lee, michael, kim, dean]
System.out.println(surnames); // [momo, jesus, danger, habbo]

改进

• 使用String.split()
• 为每个循环使用一个

for (String s : name_list) {
    String[] parts = s.split("\\s+");
    firstNames.add(parts[0]);
    surnames.add(parts[1]);
}

Answer 2

for(int i = 0; i < name_list.length; i++){
    String[] split_name = name_list[i].split(" ");
    int x = name_list[i].indexOf(" ");

    String firstName = name_list[i].substring(0,x);
    firstNames.add(firstName);
    //indexOf would be useful when surname has space separated more tahn
    // one owrd
    String surname = name_list[i].substring(x+1);
    surnames.add(surname);

}

for(int i=0; i<firstNames.size(); ++i){
    
    System.out.println(firstNames.get(i));
    System.out.println(surnames.get(i));
}