Question

我正在从网址中检索图片。而不是缓存图像，是否有可能将它存储在SQLite数据库中？

                /** Simple Constructor saving the 'parent' context. */
                public ImageAdapter(Context c) { this.myContext = c; }





                /** Returns the amount of images we have defined. */
                public int getCount() { return this.myRemoteImages.length; }

                /* Use the array-Positions as unique IDs */
                public Object getItem(int position) { return position; }
                public long getItemId(int position) { return position; }

                /** Returns a new ImageView to
                * be displayed, depending on
                * the position passed. */
                public View getView(int position, View convertView, ViewGroup parent) {
                ImageView i = new ImageView(this.myContext);

                try {

                                URL aURL = new URL(myRemoteImages[position]);
                                URLConnection conn = aURL.openConnection();

                                conn.connect();

                                InputStream is = conn.getInputStream();  
                                /* Buffered is always good for a performance plus. */
                                BufferedInputStream bis = new BufferedInputStream(is);
                                /* Decode url-data to a bitmap. */

                                Bitmap bm = BitmapFactory.decodeStream(bis);
                                bis.close();
                                is.close();
                                Log.v(imageUrl, "Retrieving image");

                                /* Apply the Bitmap to the ImageView that will be returned. */
                                i.setImageBitmap(bm);
                        } catch (IOException e) {

                                Log.e("DEBUGTAG", "Remtoe Image Exception", e);
                        }

                /* Image should be scaled as width/height are set. */
                i.setScaleType(ImageView.ScaleType.FIT_CENTER);
                /* Set the Width/Height of the ImageView. */
                if(Build.VERSION.SDK_INT >= 11){
                    i.setLayoutParams(new Gallery.LayoutParams(450, 300));
                return i;
                }
                else{
                    i.setLayoutParams(new Gallery.LayoutParams(125, 125));
                    return i;
                }

                }

                /** Returns the size (0.0f to 1.0f) of the views
                * depending on the 'offset' to the center. */
                public float getScale(boolean focused, int offset) {
                /* Formula: 1 / (2 ^ offset) */
                return Math.max(0, 1.0f / (float)Math.pow(2, Math.abs(offset)));
                }
                }

编辑：设置imageAdapter以在图库中加载图像

((Gallery) findViewById(R.id.gallery))
                          .setAdapter(new ImageAdapter(MainMenu.this));

Answer 1

protected Drawable Imagehandler(String url) {
        try {
            url=url.replaceAll(" ", "%20");
            InputStream is = (InputStream)this.fetch(url);
            Drawable d = Drawable.createFromStream(is, "src");
            return d;
        } catch (MalformedURLException e)
        {   
            System.out.println(url);
            System.out.println("error at URI"+e);
            return null;
        } 
        catch (IOException e) 
        {
            System.out.println("io exception: "+e);
            System.out.println("Image NOT FOUND");
            return null;
        } 
    }

    protected Object fetch(String address) throws MalformedURLException,IOException {
        URL url = new URL(address);
        Object content = url.getContent();
        return content;
    }

这会在运行时将imageUrl转换为Drawable，然后将Drawable设置为Gallery的Imageview

Answer 2

你可以将图像存储为数据库中的BLOB，

public static byte[] urlToImageBLOB(String url) throws IOException {
        httpclient = new DefaultHttpClient();
        entity = null;
        httpGet = new HttpGet(url);
        response = httpclient.execute(httpGet);
        if (response.getStatusLine().getStatusCode() == HttpStatus.SC_OK) {
            entity = response.getEntity();
        }
        return EntityUtils.toByteArray(entity);
    }

获取

public static Bitmap getImageFromBLOB(byte[] mBlob) {
        byte[] bb = mBlob;
        return BitmapFactory.decodeByteArray(bb, 0, bb.length);

    }

//设置imageView.setImageBitmap(getImageFromBLOB(cursor.getBlob(object.getColumnIndex("book_thumb"))));

Answer 3

以下是您在外部存储空间中存储数据的链接：External storage

链接说明放置文件的位置（如果要使用外部存储），以及如何检查外部存储是否可用。

编辑：如何访问文件，在“访问外部存储上的文件”主题下进行了解释。

您应该在API 8或更高版本中调用getExternalFilesDir()来获取代表您的应用程序根目录的File。然后，您可以像平常一样读取和写入文件（例如，使用文件数据的FileWriter和FileReader）

如何将从url中检索到的图像存储在SQLite数据库中？

3 个答案: