如何检查两个字符串是否包含相同的字母?

时间:2011-07-24 15:54:05

标签: php string match

$textone = "pate"; //$_GET
$texttwo = "tape";
$texttre = "tapp";

if ($textone ??? $texttwo) {
echo "The two strings contain the same letters";
}
if ($textone ??? $texttre) {
echo "The two strings NOT contain the same letters";
}

我在寻找什么if声明?

2 个答案:

答案 0 :(得分:11)

考虑到以下两个变量,我想一个解决方案可能是:

$textone = "pate";
$texttwo = "tape";


1。首先,拆分字符串,得到两个字母数组:

$arr1 = preg_split('//', $textone, -1, PREG_SPLIT_NO_EMPTY);
$arr2 = preg_split('//', $texttwo, -1, PREG_SPLIT_NO_EMPTY);

请注意,正如@Mike在评论中指出的那样,不是像我之前那样使用preg_split(),对于这种情况,最好使用str_split()

$arr1 = str_split($textone);
$arr2 = str_split($texttwo);


2. 然后,对这些数组进行排序,因此字母按字母顺序排列:

sort($arr1);
sort($arr2);


3. 之后,内爆数组,创建单词,其中所有字母都按字母顺序排列:

$text1Sorted = implode('', $arr1);
$text2Sorted = implode('', $arr2);


4. 最后,比较这两个

if ($text1Sorted == $text2Sorted) {
    echo "$text1Sorted == $text2Sorted";
}
else {
    echo "$text1Sorted != $text2Sorted";
}



将这个想法变成比较函数会给你以下部分代码:

function compare($textone, $texttwo) {
    $arr1 = str_split($textone);
    $arr2 = str_split($texttwo);

    sort($arr1);
    sort($arr2);

    $text1Sorted = implode('', $arr1);
    $text2Sorted = implode('', $arr2);

    if ($text1Sorted == $text2Sorted) {
        echo "$text1Sorted == $text2Sorted<br />";
    }
    else {
        echo "$text1Sorted != $text2Sorted<br />";
    }
}


并在您的两个单词上调用该函数

compare("pate", "tape");
compare("pate", "tapp");

会得到以下结果:

aept == aept
aept != appt

答案 1 :(得分:0)

使用===!==

if ($textone === $texttwo) {
    echo "The two strings contain the same letters";
}else{
    echo "The two strings NOT contain the same letters";
}

if ($textone === $texttwo) {
    echo "The two strings contain the same letters";
}

if ($textone !== $texttwo) {
    echo "The two strings NOT contain the same letters";
}