PHP＆amp; MySQL数组问题

Question

我正在尝试将文章ID添加到标题，摘要和内容中，但我不知道怎么做可以帮助我解决这个问题。

这是给我问题的代码。

while($row = mysqli_fetch_assoc($run)) {
    $id[] = $row['id'];
    $title[] = $row['id']['title'];
    $summary[] = $row['id']['summary'];
    $content[] = $row['id']['article_content'];
}

以下是我的PHP和MySQL代码。

$x = 0;
$con = null;
$search = $_REQUEST['search'];
$id = array();
$title = array();
$summary = array();
$content = array(); 

$search_explode = mysqli_real_escape_string($dbc, $search);
$search_explode = explode(' ', $search_explode);

foreach($search_explode as $search_each) {
    $x++;
    if($x == 1){
        $con .= " article_content LIKE '%$search_each%' OR title LIKE '%$search_each%' OR summary LIKE '%$search_each%'";
    } else {
        $con .= " OR article_content LIKE '%$search_each%' OR title LIKE '%$search_each%' OR summary LIKE '%$search_each%'";
    }
}

$con = "SELECT users.*, users_articles.* FROM users_articles
              INNER JOIN users ON users_articles.user_id = users.user_id
              WHERE ($con) 
              AND users.active IS NULL
              AND users.deletion = 0";

$run =  mysqli_query($dbc, $con);
$search_term = mysqli_num_rows($run);

while($row = mysqli_fetch_assoc($run)) {
    $id[] = $row['id'];
    $title[] = $row['id']['title'];
    $summary[] = $row['id']['summary'];
    $content[] = $row['id']['article_content'];
}

Answer 1

while($row = mysqli_fetch_assoc($run)) {
    // $id[] = $row['id']; you probably do not need this anymore
    $title[$row['id']]   = $row['title'];
    $summary[$row['id']] = $row['summary'];
    $content[$row['id']] = $row['article_content'];
}

// at this point, each array will contain rows
// with keys matching the corresponding id
var_dump($title);
var_dump($summary);
var_dump($content);

Answer 2

$title[] = $row['id']['title'];
$summary[] = $row['id']['summary'];
$content[] = $row['id']['article_content'];

mysqli_fetch_assoc将获取关联的数组。像$row['summary']那样直接访问数据应该可以解决您的问题。

修改

你在谈论字符串连接吗？

$title[] = $row['id'] . ' ' . $row['title'];
$summary[] = $row['id'] . ' ' . $row['summary'];
$content[] = $row['id'] . ' ' . $row['article_content'];

上面的代码基本上会将标题/摘要/内容附加到您的文章ID并将其添加到相应的数组中。

Answer 3

我不确定你想要实现什么，但我会建议以下解决方案。请看一下。

CREATE TABLE IF NOT EXISTS users (
  user_id int(11) NOT NULL AUTO_INCREMENT,
  name varchar(100) NOT NULL,
  deletion int(11) NOT NULL DEFAULT '0',
  active int(11) NOT NULL DEFAULT '1',
  PRIMARY KEY (user_id)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ;


--

-- Dumping data for table users

INSERT INTO users (user_id, name, deletion, active) VALUES
(1, 'John', 0, 1),
(2, 'George', 0, 1);



--

-- Table structure for table users_articles

CREATE TABLE IF NOT EXISTS users_articles (
  id int(11) NOT NULL AUTO_INCREMENT,
  user_id int(11) NOT NULL,
  article_content varchar(255) NOT NULL,
  title varchar(255) NOT NULL,
  summary text NOT NULL,
  PRIMARY KEY (id)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=5 ;

--

-- Dumping data for table users_articles

INSERT INTO users_articles (id, user_id, article_content, title, summary) VALUES
(1, 1, 'test', 'test', 'test test test  test'),
(2, 2, 'test 2', 'test 2', 'test test'),
(3, 1, 'test 3', 'test 3 ', 'test test test  test 3'),
(4, 2, 'test 3', 'test 3', 'test test 3');

            <?php
            error_reporting(E_ALL);
            ini_set('display_errors', 1);
            $mysqli = new mysqli("localhost", "root", "", "articles");

            /* check connection */
            if ($mysqli->connect_errno) {
                printf("Connect failed: %s\n", $mysqli->connect_error);
                exit();
            }

            /* Select queries return a resultset */
            $con = 1;
            $sql = "SELECT users.*, users_articles.* FROM users_articles
                          INNER JOIN users ON users_articles.user_id = users.user_id
                          WHERE ($con) 
                          AND users.active = 1
                          AND users.deletion = 0";
            $results = array();              
            if ($result = $mysqli->query($sql)) {
                printf("Select returned %d rows.\n", $result->num_rows);
                print   '<pre>';
                while ($row = $result->fetch_assoc()) {
                    $results[] = $row;
                }
                print_r($results);
            print   '</pre>';
                /* free result set */
                $result->close();
            }


            $mysqli->close();
            ?>

当你迭代$ results时你可以连接id和其他字段，在这种情况下你也可以在其他区域使用结果数组。